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gregori [183]
3 years ago
15

What are five number pairs that solve the equation vw=0 ?

Mathematics
1 answer:
prohojiy [21]3 years ago
3 0
The following pairs all solve the equation  [ v w = 0 ] :

1 and 0
2 and 0
3 and 0
4 and 0
0 and 5
0 and 6
0 and 7
0 and 8
1 million and 0
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Find the area of an equilateral triangle with a side of 6 inches.
sweet-ann [11.9K]

Answer:

9\sqrt{3} in²

Step-by-step explanation:

The area (A) of an equilateral triangle is calculated as

A = \frac{s^2\sqrt{3} }{4} ( s is the length of a side )

Here s = 6, thus

A = \frac{6^2\sqrt{3} }{4} = \frac{36\sqrt{3} }{4} = 9\sqrt{3} in²

6 0
3 years ago
If tsr = 84 what is the value of x? SQ bisects TSR RSQ= 3x-9
dsp73
We know that
 ∠ TSR = 84°

if SQ bisects ∠ <span>TSR
then 
</span>∠ RSQ = ∠ TSR/2
<span>so
</span>∠ RSQ = (1/2)*84°----- 42°
∠ RSQ = 3x-9
3x-9=42-------> 3x=42+9------> 3x=51-----> x=51/3-----> x=17°
<span>
the answer is
</span>x=17°<span>

</span>
7 0
3 years ago
Read 2 more answers
Vill all three students complete a sign at the same time? Explain your
7nadin3 [17]
I think it would be 23 bags without any cookies left over
4 0
2 years ago
How many solutions exist for the system of equations graphed below?
tamaranim1 [39]

Considering the given graph, the number of solutions for the system of equations is given by:

b.) one

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In a graph, the number of solutions is given by the number of times the lines intersect. Hence, in this problem, the system has one solution, and option b is correct.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

4 0
2 years ago
Given: △CGF ,CG=GF=CF=and, KOPS is a square inside this triangle with one side on CF and its two vertices on CG and GF
shepuryov [24]

Answer:

  AKPOS/ACGF = 28√3 -48 ≈ 0.497423

Step-by-step explanation:

Let's assume the square is a unit square. Then the height of the triangle is ...

  1 +(√3)/2 = h

and half the base of the triangle is ...

  h/√3 = (√3)/3 +1/2 = b/2

The area of the triangle is the product of these:

  A = (1/2)bh

  = (2 +√3)/2 × (3 +2√3)/6

  = (6 +3√3 +4√3 +6)/12 = (12 +7√3)/12

So, the ratio of the area of the square to that of the triangle is the inverse of this, or ...

  (square area)/(triangle area) = 12/(12+7√3)

  (square area)/(triangle area) = 28√3 -48

8 0
3 years ago
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