Answer:
<em><u>use</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>ope</u></em><em><u>ning</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>cl</u></em><em><u>osing</u></em><em><u> </u></em><em><u>tags</u></em><em><u> </u></em>
<em><u>[</u></em><em><u>Tex]</u></em><em><u> </u></em><em><u>[</u></em><em><u>\</u></em><em><u>t</u></em><em><u>e</u></em><em><u>x</u></em><em><u>]</u></em><em><u> </u></em><em><u>ok</u></em>
Answer:
Explanation:
class TimeToSleep() {
main bunch of stuff (string argos) {
int age;
string comedy;
bool guess;
public bool imTheMasterMethod() {
guess = true;
while (guess) {
comedy = "You forgot to put the flowchart, you meathead!";
println(comedy);
scan("%d", &age);
if (age < 18) {
println("Go to sleep kiddo!");
}
}
}
}
}
Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) =
=
= 0.0316
For x = 120, sample proportion(p) =
=
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z <
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )
You cant, you have to either delete items off to gain some storage back or go buy an ipad with more storage