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3 years ago

Plz answer my question

Mathematics

1 answer:

Drupady [299]3 years ago

3 0

Answer:

2a^4 / b^5

Step-by-step explanation:

(2a^2 / b) x ( a / b^2) ^2

= (2a^2 / b) x (a^2 / b^4)

= 2a^4 / b^5

(p.s if you are not gonna do it don't say "no thanks" and leech off this poor man's points)

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In the circle, m arc BC = 72°. The diagram is not drawn to scale. What is m angle BCP

QveST [7]

Answer:

Measure of ∠BCP is 36°

Step-by-step explanation:

Given the circle in which measure of arc BC is 72°

we have to find the measure of angle BCP.

m∠BOC=∠2=72°

By theorem angle subtended at the centre is twice the angle formed at the circumference of circle.

∴ ∠2=2∠1 ⇒ 72=2∠1

⇒ ∠1=36°

By alternate segment theorem which states that

The angle formed between a chord and a tangent through one of the end points of chord is equals to angle in alternate segment.

⇒ ∠3=∠1=36°

Hence, measure of ∠BCP is 36°

Option D is correct

5 0

3 years ago

Read 2 more answers

The probability that your call to a service line is answered in less than 30 seconds is 0.85. Assume that your calls are indepen

aev [14]

Answer:

a) 0.1720

b) 0.8298

c) 19

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.85$

(a) If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X = 9)$ when $n = 12$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{12,9}.(0.85)^{9}.(0.15)^{3} = 0.1720$

(b) If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X \geq 16)$ when $n = 20$

$P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 16) = C_{20,16}.(0.85)^{16}.(0.15)^{4} = 0.1821$

$P(X = 17) = C_{20,17}.(0.85)^{17}.(0.15)^{3} = 0.2428$

$P(X = 18) = C_{20,18}.(0.85)^{18}.(0.15)^{2} = 0.2293$

$P(X = 19) = C_{20,19}.(0.85)^{19}.(0.15)^{1} = 0.1368$

$P(X = 20) = C_{20,20}.(0.85)^{20}.(0.15)^{0} = 0.0388$

$P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1821 + 0.2428 + 0.2293 + 0.1368 + 0.0388 = 0.8298$

(c) If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

$E(X) = np$

In this question, we have $n = 22$

$E(X) = 22*0.85 = 18.7$

The nearest integer to 18.7 is 19.

7 0

3 years ago

Along the Oregon trail the trading post in fort Laramie, Wyoming, sold a 16 pound of beef je rky for 5.92 what was the cost per

MaRussiya [10]

You need to divide the amount from the quantity
So 5.92 divide by 166= $0.37 per pound.

3 0

3 years ago

How old is ashley 100 points and brainly

Stells [14]

Answer:

9 years old

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

What are the best approximations of the solutions to this system?

Scilla [17]

(-1.2,-2.0) and (1.9,2.2) are the best approximations of the solutions to this system.

Option B

Step-by-step explanation:

Here, we have a graph of two functions from which we need to find the approximate value of common solutions. Let's find this:

First look at where we have intersection points, In first quadrant & in third quadrant.

At first quadrant:

Draw perpendicular lines from x-axis & y-axis from this point . After doing this we can clearly see that the perpendicular lines cut x-axis at x=1.9 and y-axis at y=2.2. So, one point is (1.9,2.2)

At Third quadrant:

Draw perpendicular lines from x-axis & y-axis from this point. After doing this we can clearly see that the perpendicular lines cut x-axis at x=-1.2 and y-axis at y= -2.0. So, other point is (-1.2,-2.0).

5 0

3 years ago