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3 years ago

Please write a separate sentence for each of these words

Mathematics

1 answer:

tester [92]3 years ago

7 0

Answer:

After graduation, I got a job with a commerce firm selling various products.

In the United States, our currency is the American dollar.

Looking at Egyptian hieroglyphics, it is amazing to think that people could record their thoughts such a long time ago.

Ancient Egyptians used papyrus to make things such as baskets or sandals.

It can be quite costly to export goods internationally.

Parchment was an old type of paper, that was much thicker than modern paper today.

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The author drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 200 times. Here are the observed

algol [13]

Answer:

$\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860$

$p_v = P(\chi^2_{5} >5.860)=0.32$

Since the p value is higher than the significance level assumed 0.05 we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we can assume that we have equally like results.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Number: 1, 2 , 3 , 4 , 5 ,6

Frequency: 27, 31, 42, 40, 28, 32

We need to conduct a chi square test in order to check the following hypothesis:

H0: The outcomes are equally likely.

H1: The outcomes are not equally likely.

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The observed values are given:

$O_{1}=27$ $O_{2}=31$

$O_{3}=42$ $O_{4}=40$

$O_{5}=28$ $O_{6}=32$

The expected values are given by:

$E_{1} =\frac{1}{6}*200=33.33$ $E_{2} =\frac{1}{6}*200=33.33$

$E_{3} =\frac{1}{6}*200=33.33$ $E_{4} =\frac{1}{6}*200=33.33$

$E_{5} =\frac{1}{6}*200=33.33$ $E_{6} =\frac{1}{6}*200=33.33$

And now we can calculate the statistic:

$\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860$

Now we can calculate the degrees of freedom for the statistic given by:

$df=Categories-1=6-1=5$

And we can calculate the p value given by:

$p_v = P(\chi^2_{5} >5.860)=0.32$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(5.860,5,TRUE)"

4 0

3 years ago

Help pls show work if needed!!

andrew-mc [135]

Answer:

False

True

true

Step-by-step explanation:

65x+105=y

Substitute 6 for x to find the cost for 6 classes

65(6)+105=y

390+105=y

495=y

4 0

3 years ago

{x|x€Z^x<8}<br> Please someone help me what should be the elements in the set

joja [24]

What how is this a problem and how are you in middle school

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3 years ago

A radio station sells buttons and bumper stickers at a local fair. The buttons cost $2.95 each, and the bumper stickers cost $3.

MA_775_DIABLO [31]

you question isn't quite clear.....

3 0

3 years ago

In Vindales wig shop 1/4 of the wigs are blonde and 1/4 of wigs are brunette. What fraction of the wigs are either blonde or bru

alisha [4.7K]

Answer:

The answer is 2/4

Step-by-step explanation:

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