(4,-1) turns into (1,4) because the equation for that is (x,y)->(y•-1,x)
Answer:
please what shape is this
Answer:
w = 15
Step-by-step explanation:
-9(w + 585) = -360w
-9w -5265 = -360w
351w = 5265
w=15
Answer: The height of the triangle is: " 3.5 cm " .
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<u>
Note</u>: The formula/equation for the area, "A" , of a triangle is:
A = (1/2) * b * h ; or write as: A = (b * h) / 2 ;
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in which: "A = area of the triangle" ;
"b = base length" ;
"h = "[perpendicular] height" ;
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Given: h = (b/2) ;
A = 12.25 cm²
{Note: Let us assume that the given area was "12.25 cm² " .}.
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We are to find the height, "h" ;
The formula for the Area, "A", is: A = (b * h) / 2 ;
Let us rearrange the formula ;
to isolate the "h" (height) on one side of the equation;
→ Multiply EACH side of the equation by "2" ; to eliminate the "fraction" ;
2*A = [ (b * h) / 2 ] * 2 ;
to get: " 2A = b * h " ;
↔ " b * h = 2A " ;
Divide EACH SIDE of the equation by "b" ; to isolate "h" on one side of the equation:
→ (b * h) / b = (2A) / b ;
to get:
→ h = 2A / b ;
Since "h = b/2" ; subtitute "b/2" for "h" ;
Plug in: "12.25 cm² " for "A" ;
→ b/2 = 2A/b ; → Note: " 2A/b = [2* (12.25 cm²) ] / b " ;
Note: " 2* (12.25 cm²) = 24.5 cm² ;
Rewrite as:
→ b/2 = (24.5 cm²) / b ;
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Cross-multiply: b*b = (24.5 cm²) *2 ;
to get: b² = 49 cm² ;
Take the "positive square root" of each side of the equation" ;
to isolate "b" on one side of the equation ; & to solve for "b" ;
→ +√(b²) = +√(49 cm²) ;
→ b = 7 cm ;
Now, we want to solve for "h" (the height) :
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→ h = b / 2 = 7 cm / 2 = 3.5 cm ;
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Answer: The height of the triangle is: " 3.5 cm <span>" .
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Step-by-step explanation:
ATQ,
Let d be the number of kilograms of dark chocolate she buys and m be the number of kilograms of milk chocolate she buys.
She needs to buy 120 kg of chocolate in total for her next order, and her recipe calls for twice the amount of dark chocolate as milk chocolate.
So,
m = 2d .....(1)
m + d = 120 ...(2)
We can also solve the above equations,
Put m = 2d in equation (2)
2d + d = 120
3d=120
d = 40
Put d = 40 in equation (1)
m = 2(40)
m = 80
Hence, she will need 40 kg of dark chocolate and 80 kg of milk chocolate.
