13)
there are 2π radians in 1 revolution, and there are 60 seconds in 1 minute, so keeping that in mind, then,

14)


15)
what is the radians per seconds "w" in revolutions per minute? just another conversion like in 13)
Answer:
1 7/8
Step-by-step explanation:
3/8 * 5/1 = 15/8
<-- First multiply 3/8 by 5
----------------------------------------------
15/8 = 1 with a remainder of 7
<-- Then convert 15/8 to a mixed number by dividing 15 by 8
15/8 = 1 7/8
Answer:
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
||Vel_jet_r|| = 465.993 mph
Step-by-step explanation:
We need to decompose the velocity of the wind into a component that can be added (or subtracted from the velocity of the jet)
The velocity of the jet
500 mph North
Velocity of the wind
50 mph SouthEast = 50 cos(45) East + 50 sin (45) South
South = - North
Vel_ wind = 50 cos(45) mph East - 50 sin (45) mph North
Vel _wind = 35.35 mph East - 35.35 mph North
This means that the resulting velocity of the jet is equal to
Vel_jet_r = (500 mph - 35.35 mph) North + 35.35 mph East
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
An the jet has a magnitude velocity of
||Vel_jet_r|| = sqrt ((464.645 mph)^2 + (35.35 mph)^2)
||Vel_jet_r|| = 465.993 mph
Answer:
x=7
Step-by-step explanation:
5x-9=8x-30
8x-5x=-9+30
3x=21
x=21/3=7
Answer:
Option D.
The discriminat is equal to 24 which
Step-by-step explanation:
The quadratic equation is
-2x² + 3 = 0
Discriminat in quadratic equation tells us the number of solution a quadratic equation has.
For example, the quadratic equation
Ax² + bx + c = 0 will have a discriminat of b² - 4ac.
b² - 4ac is equal to the value of the discriminat and equal to the number of solutions the quadratic equation has.
In our question, we have -2x² + 3 = 0
A = -2
B = 0
C = 3
b² - 4ac = 0
Substitute the values into the above equation.
0² - 4(-2 ×3) = 0
0 + -4 × -6 = 0
24 = 0
The discriminat of the equation is 24