Question

Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1?

Answer 1

Answer:

It has no solution.

Step-by-step explanation:

The given equation is

$\frac{3}{4z}-\frac{1}{4z+1}=\frac{2}{4z+1}$

We multiply through with $4z(4z+1)$

$4z(4z+1)*\frac{3}{4z}-4z(4z+1)*\frac{1}{4z+1}=4z(4z+1)*\frac{2}{4z+1}$

$3(4z+1)-4z=8z$

$12z+3-4z=8z$

$12z-4z-8z=-3$

$0=-3$

This is never true.

Therefore the equation has n solution