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Morgarella [4.7K]
2 years ago
7

While performing the ″roll out the sunshine″ dance, what do your arms do at the very beginning of the sequence?

Mathematics
2 answers:
exis [7]2 years ago
8 0
Isnt there a youtube video with that? Im not sure... But thats where ill look for proof.. :)
mash [69]2 years ago
5 0
Wut you wanna do is  extend our arms out wide
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Help I truly don’t understand anything
andrezito [222]
There are a total of 68 cars in the parking lot (sum of all values on the table).

Selecting blue OR a chevy, means all blue and all chevies are valid choices...there are 7+9+8+7+5 (blue cars and chevy cars) = 36:
36/68 =  9/17

Selecting blue AND a chevy - There are 8 blue chevies: 
<span>8/68= </span>2/17

GIVEN that the car is blue means we're <em>only selecting from </em>the 7+9+8 = 24 blue cars on the lot which are chevies...and there are 8 blue chevies:
8/24 = 1/3


6 0
3 years ago
I need help please.
IgorLugansk [536]

Answer:

13 - 17\sqrt{11}

Step-by-step explanation:

Using the rule

\sqrt{a} × \sqrt{a} = a

Each term in the second factor is multiplied by each term in the first factor, that is

2\sqrt{11} (\sqrt{11} - 9 ) + 1 (\sqrt{11} - 9 )

Distribute both parenthesis

= (2 × 11) - 18\sqrt{11} + \sqrt{11} - 9

= 22 - 17\sqrt{11} - 9

= 13 - 17\sqrt{11}

7 0
3 years ago
2. What does y equal? *<br> y+3/4 = 6
kakasveta [241]

Answer:

3rd option

Step-by-step explanation:

Given

y + \frac{3}{4} = 6 ( multiply through by 4 to clear the fraction

4y + 3 = 24 ( subtract 3 from both sides )

4y = 21 ( divide both sides by 4 )

y = \frac{21}{4} = 5 \frac{1}{4}

6 0
3 years ago
how so you solve 5x+27=9(x+3)-4x and is this a conditional equation, an identity, or an inconsistent equation
Vikentia [17]

To solve this, follow these steps:

5x + 27 = 9 (x+3) - 4x

Distribute the 9 within the parenthesis:

5x + 27 = 9x + 27 - 4x

Then combine like terms:

5x + 27 = 5x + 27

These two then cancel each other out completely.

This is an identity because an identity in math is when both equations equal each other, which is shown above.

Hope this helps!

5 0
3 years ago
Given two vectors A=2i+3j+4k,B=i-2j+3k find the magnitude and direction of sum<br>(physics question)
Law Incorporation [45]

Answer:

Magnitude =\sqrt{59} \\\\Direction \: of \: \overrightarrow{A + B} = \frac{3}{\sqrt {59}} , \:\frac{1}{\sqrt {59}} , \:\frac{7}{\sqrt {59}}

Step-by-step explanation:

A=2i+3j+4k

B=i-2j+3k

Sum of the vectors:

A + B = 2i+3j+4k + i-2j+3k = 3i + j + 7k

Magnitude =\sqrt{3^2 + 1^2+ 7^2} \\\\Magnitude =\sqrt{9+1+49} \\\\Magnitude =\sqrt{59}

Direction of the sum of the vectors:

\widehat{A + B} =\frac{\overrightarrow{A + B}}{Magnitude\: of \:\overrightarrow{A + B}} \\\\\widehat{A + B} =\frac{3i + j + 7k}{\sqrt {59}} \\\\\widehat{A + B} =\frac{3}{\sqrt {59}} i +\frac{1}{\sqrt {59}} j+\frac{7}{\sqrt {59}} k\\\\Direction \: of \: \overrightarrow{A + B} = \frac{3}{\sqrt {59}} , \:\frac{1}{\sqrt {59}} , \:\frac{7}{\sqrt {59}} \\\\

3 0
2 years ago
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