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4 years ago

8

Need help with a math question PLEASE HELP

1 answer:

dmitriy555 [2]4 years ago

8 0

Answer:

tbh bro i need help to

Step-by-step explanation:

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Julio wants to find the volume of a small pebble. He drops it into a graduated cylinder filled with 30.0 mL of water.

dezoksy [38]

Answer:

By calculating water displacement

Step-by-step explanation:

Because Julio knows the volume of water in the graduated cylinder, by dropping the pebble in, he can record the new volume of both the water and pebble. Subtracting the volume of the water from the volume of both will leave him with the volume of the pebble. This technique is water displacement.

8 0

4 years ago

Read 2 more answers

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Reika [66]

Answer:

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Step-by-step explanation:

8 0

3 years ago

The number of bacteria, B, in a refrigerated food is given by the function b(t) = 15t2 - 60t + 125, where t is the temperature o

Nimfa-mama [501]

Answer: $b(t(h))=135h^2+180h+125$

Step-by-step explanation:

Given: The number of bacteria, B, in a refrigerated food is given by the function $b(t)=15t^2-60t+125$ , where t is the temperature of food in degrees Fahrenheit.

The function $t(h)=3h+4$ gives the temperature, t, of the food h hours after being removed from the refrigerator.

Now, the number bacteria in the food in h hours is given by:-

$b(t(h))=15(3h+4)^2-60(3h+4)+125\\=15(9h^2+16+24h)-180h-240+125\\=135h^2+240+360h-180h-240+125\\=135h^2+180h+125$

So, The number bacteria in the food in h hours is given by:

$b(t(h))=135h^2+180h+125$

4 0

3 years ago

A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.

noname [10]

Answer:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

Step-by-step explanation:

Given

$Volume = 128ft^3$

$L = 2W$

$Base\ Cost = \$9/ft^2$

$Sides\ Cost = \$6/ft^2$

Required

The dimension that minimizes the cost

The volume is:

$Volume = LWH$

This gives:

$128 = LWH$

Substitute $L = 2W$

$128 = 2W * WH$

$128 = 2W^2H$

Make H the subject

$H = \frac{128}{2W^2}$

$H = \frac{64}{W^2}$

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

$A = LW + 2(WH + LH)$

The cost is:

$Cost = 9 * LW + 6 * 2(WH + LH)$

$Cost = 9 * LW + 12(WH + LH)$

$Cost = 9 * LW + 12H(W + L)$

Substitute: $H = \frac{64}{W^2}$ and $L = 2W$

$Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)$

$Cost =18W^2 + \frac{768}{W^2}*3W$

$Cost =18W^2 + \frac{2304}{W}$

To minimize the cost, we differentiate

$C' =2*18W + -1 * 2304W^{-2}$

Then set to 0

$2*18W + -1 * 2304W^{-2} =0$

$36W - 2304W^{-2} =0$

Rewrite as:

$36W = 2304W^{-2}$

Divide both sides by W

$36 = 2304W^{-3}$

Rewrite as:

$36 = \frac{2304}{W^3}$

Solve for $W^3$

$W^3 = \frac{2304}{36}$

$W^3 = 64$

Take cube roots

$W = 4$

Recall that:

$L = 2W$

$L = 2 * 4$

$L = 8$

$H = \frac{64}{W^2}$

$H = \frac{64}{4^2}$

$H = \frac{64}{16}$

$H = 4$

Hence, the dimension that minimizes the cost is:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

8 0

3 years ago

Solve these algebraic fractions please with explanation would be great

Pavlova-9 [17]

Answer:

look above

Step-by-step explanation:

hope it helps

4 0

2 years ago