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kari74 [83]
4 years ago
13

Why can’t the absolute value of anything equal a negative number?

Mathematics
1 answer:
MrMuchimi4 years ago
4 0

Answer:

The absolute value makes the number inside it, a positive

Step-by-step explanation:

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Find the slope of a line parallel to each given line
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Answer:

7) D

8) A

9) A

10) D

11) C

12) B

Step-by-step explanation:

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3 years ago
PLEASE HELP!!! I cannot figure this problem out.
nataly862011 [7]

Answer:

A and C.

Step-by-step explanation:

to get rid of the square root & n, you would have to multiply it by n on both sides of the equation, giving you r^n=a.

also to get rid of the square root & n, you can also multiply both sides of a and r by the exponential fraction with n as the denominator:

\sqrt[n]{a} =r \\(a)^\frac{1}{n} = r\\a\frac{1}{n} = r

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3 years ago
At a concert, floor tickets are $20 each, and
Pani-rosa [81]

Answer: 352 tickets

Step-by-step explanation:

because multiplying $20 floor tickets by 324 (how many were sold) gives you 6480

subtract from 10000

gives you 3520 (amount made from balcony)

divide by $10

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3 years ago
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I really need help again 8th grade math
valina [46]

Answer:

1

Step-by-step explanation:

The picture is too small but I believe the answer is 1.

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3 years ago
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Examine the required sample size needed to be able to
Xelga [282]

Answer:

n=(\frac{2.33(500)}{10})^2 =13572.25 \approx 13573

And if we use a sample level of n =2000 the margin of error would be higher as we can see here:

ME=2.33\frac{500}{\sqrt{2000}}=26.05  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=500 represent the population standard deviation assumed

n represent the sample size  (variable of interest)

Confidence =98% or 0.98

ME = 10 represent the margin of error desired

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =10 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.01;0;1)", and we got z_{\alpha/2}=2.33, replacing into formula (b) we got:

n=(\frac{2.33(500)}{10})^2 =13572.25 \approx 13573

So the answer for this case would be n=13573 rounded up to the nearest integer

And if we use a sample level of n =2000 the margin of error would be higher as we can see here:

ME=2.33\frac{500}{\sqrt{2000}}=26.05    

3 0
4 years ago
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