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Artemon [7]
3 years ago
10

Plz help !!!!!!!!!!!!!

Mathematics
1 answer:
creativ13 [48]3 years ago
3 0

Answer: \bold{\large{a^{\frac{1}{2}}b^{\frac{1}{2}}}}

<u>Step-by-step explanation:</u>

\sqrt{ab}=(ab)^{\frac{1}{2}}=\large{\boxed{a^{\frac{1}{2}}b^{\frac{1}{2}}}}

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Mickey went down to the pet store and bought 115 pounds of bird seed. Mickey gave 7 of the bird seed to Daisy, and Daisy gave
Anni [7]

Answer: Frank received 5 pounds of seed

Step-by-step explanation: Well if daisy gives 5 pounds of seed to frank then frank receives 5 pounds of seeds

5 0
3 years ago
180 people in a cinema <br> 3/5 are adults<br> 1/4 are female<br> How many of the adults are female?
cupoosta [38]
<span>1 way
the nootebook
180 * 3/5 = 108
108 * 1/4 = 27
.....................................................

Woman is an adult

</span><span>1. We compute how many adults
</span>180 *  \frac{3}{5}  =  \frac{180*3}{5}  =  \frac{540}{5} = 108&#10;&#10;

2 <span>1/4 of adults are women
</span>
108 * 1/4 = 28

Answer 27
............................................................

2 way
the nootebook
180 * 3/5*1/4 = 27


8 0
3 years ago
Read 2 more answers
The mean of Holly's first six math quiz scores was 75%. After taking the seventh quiz, her mean score rose to 77%. What was Holl
alexandr1967 [171]

Let x represent Holly's score on 7th math quiz.

We have been given that the mean of Holly's first six math quiz scores was 75%. This means that the average on 1st 6 math quizzes is 75.

To find the total scores on 1st 6 math quizzes, we will multiply 75 by 6 that is 75\times 6 =450.

We will use average formula to find test scores on 7th math quiz.

\text{Average of 7 math quizzes}=\frac{\text{Sum of scores on 7 math quizzes}}{\text{7 quizzes}}

77=\frac{x+450}{7}

Let us solve for x.

77\cdot 7=\frac{x+450}{7}\cdot 7

539=x+450

x+450=539

x+450-450=539-450

x=89

Therefore, Molly's score on the 7th math quiz was 89.

8 0
3 years ago
Find the functions domain
horrorfan [7]
The domain is the x side or the x-axises.
4 0
3 years ago
List all the ways to select two members from S with repetition. The order in which the members are selected is not important. Fo
nexus9112 [7]

Answer:

15 ways

Step-by-step explanation:

We are given that  a set S={E,F,G,H,J}

We have to find the number of ways to select two members from S with repetition.

Combination formula

\binom{n}{r}=\frac{n!}{r!(n-r)!}

We have n=5 , r= 2

Number of ways in which two members  from S can be selected when repetition is not allowed=5C_2=\frac{5!}{2!(5-2)!}

Number of ways in which two members  from S can be selected when repetition is not allowed=\frac{5\times4\times3!}{2\times1 3!]

Number of ways in which two members  from S can be selected when repetition is not allowed=5\times 2=10

When a member repeat then combination

{E,E},{F,F},{G,G},{H,H},{J,J}

There are 5 combination when a member is repeat and select two members from S.

Total number of ways in which to select two members from S with repetition =10+5=15 ways

3 0
4 years ago
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