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Arisa [49]
3 years ago
6

Consider the following graph of h(x) , a piecewise function, and determine the following answers in interval notation.

Mathematics
1 answer:
erica [24]3 years ago
3 0

Answer:

Use the digram in a double rift format to make out the number of the far number

Step-by-step explanation:

i told you

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What is the answer ?
mina [271]

Answer:

1)x=15

2)x=38

3)x=7

4)x=10

Step-by-step explanation:

3 0
3 years ago
Write 19/9 as a mixed number
Iteru [2.4K]

Answer:

2 1/9

Step-by-step explanation:

Divide 19 by 9 and get a number with a remainder

Take remainder and put it as the numerator with 9 and the denominator and with 2 as the whole number

7 0
3 years ago
Assuming x=0 and y=0, what is the quotient of 24^6y^2 + 16x^4y^3 + 8x^2y^4
Tcecarenko [31]
There is no quotient: if x is equal to zero, then your problem would simplify to a number divided by zero. As it is impossible to divide by zero, there is no answer.

6 0
3 years ago
Read 2 more answers
HELP MEEEEEEEEEEEEEEEE
Monica [59]

Answer:

Lest then 5/8

Step-by-step explanation:

Lest then 5/8

5 0
2 years ago
4.
marta [7]

Answer:

a) (x-2)(x-6) + (y-5)(y-11) =0\Rightarrow (x-4)^{2}+(y+3)^{2}=68\\C(4,-3) \:r=\sqrt{68} b) (a,b) (c, d) As long as (a,b) and (c,d) are the endpoints of of the diameter.

Step-by-step explanation:

a)

1) The reduced formula of the Circumference is given by:

(x-a)^{2}}+(y-b)^{2}=r^{2}

2) Let's expand the factored one into one closer to the pattern above:

x^{2}-8x+12+y^{2}+6y-55=0\Rightarrow x^{2}-8x+y^{2}+6y=43

3) Completing the square for both trinomials:

(x-4)^{2}+(y+3)^{2}=43+16+9\Rightarrow (x-4)^{2}+(y+3)^{2}=68

4) In the Reduced Formula, (x-a)^{2}}+(y-b)^{2}=r^{2},

C(a,b) \Rightarrow C(4,-3) \:the\:radius\:is\:r=\sqrt{68} \Rightarrow r=2\sqrt{17}

b) Using the previous example to show this:

When we  factor this way

(x-a)(x -c) + (y -b)(y-d) = 0

We are indeed, naming "a" and "b", the coordinates of (a, b) of the first endpoint and "b" and "d" the second endpoint as well.Id est, D (2, 5) and B (6,-11).

The radius, is \sqrt{68} \cong 8.25

So yes, the equation of the circle can be written as

(x-a)(x -c) + (y -b)(y-d) = 0

As long as (a,b) and (c,d) are the endpoints of of the diameter.

d_{AC}=d_{BC}=R

3 0
3 years ago
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