SORRY! BUT ALL HELP IS REALLY APPRECIATED! AND WOULD LIKE IF YOU COULD HELP A GURL OUT THANKS
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Answer:
<u>let's simplify the parenthesis first ~</u>
<u>now , bring the like terms at one side of the equation !</u>
<u>dividing</u><u> both sides of the equation by 30 ,</u>
hope helpful :)
Answer:
The 95% confidence interval estimate of the population proportion of managers who have caught salespeople cheating on an expense report is (0.5116, 0.6484).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
In the survey on 200 managers, 58% of the managers have caught salespeople cheating on an expense report.
This means that
95% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval estimate of the population proportion of managers who have caught salespeople cheating on an expense report is (0.5116, 0.6484).