So I belive you would divide 8 by 30 then subtract 8 :)
Answer:
D x^2 smaller than or equal 4
Step-by-step explanation:
if you tried to get a number on the number line and put it to fit in the equation it will just end to equal or smaller than 4
Answer:
We are given that According to government data, 75% of employed women have never been married.
So, Probability of success = 0.75
So, Probability of failure = 1-0.75 = 0.25
If 15 employed women are randomly selected:
a. What is the probability that exactly 2 of them have never been married?
We will use binomial
Formula : 
At x = 2



b. That at most 2 of them have never been married?
At most two means at x = 0 ,1 , 2
So, 


c. That at least 13 of them have been married?
P(x=13)+P(x=14)+P(x=15)



Answer:

Step-by-step explanation:
Hello,
let s assume that m+n is different from 0
we have this equation and we need to find m as a function of t, s, and n

<=>

for t-s different from 0, so t different from s
hope this helps
Answer:
81π ft³
Step-by-step explanation:
If the diameter is 6 ft, the radius is 3 ft.
The volume is V = (area of base)(height).
Here, V = (π[3 ft]²)(9 ft) = 81π ft³