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Kazeer [188]
3 years ago
8

HELP ME PLEASE!!!!!!!!!!!

Mathematics
1 answer:
telo118 [61]3 years ago
5 0

Answer:

\large\boxed{f(n)=2\cdot f(n-1)+1}

Step-by-step explanation:

f(1)=5\\\\f(2)=11=2\cdot5+1=2\cdoy f(1)+1\\\\f(3)=23=2\cdot11+1=2\cdot f(2)+1\\\\f(4)=47=2\cdot23+1=2\cdot f(3)+1\\\\f(5)=95=2\cdot47+1=2\cdot f(4)+1\\\vdots\\f(n)=2\cdot f(n-1)+1

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Which numbers is 50 divisible by 2 , 5 , 10 , 15
meriva

Answer:

2, 5, 10

Step-by-step explanation:

50 divided by 2 = 25

50 divided by 5 = 10

50 divided by 10 = 5

50 divided by 15 = NOT POSSIBLE

8 0
4 years ago
What is the area of a regular hexagon (6 sides) whose
Ganezh [65]

Step-by-step explanation:

With reference to the regular hexagon, from the image above we can see that it is formed by six triangles whose sides are two circle's radii and the hexagon's side. The angle of each of these triangles' vertex that is in the circle center is equal to 360∘6=60∘ and so must be the two other angles formed with the triangle's base to each one of the radii: so these triangles are equilateral.

The apothem divides equally each one of the equilateral triangles in two right triangles whose sides are circle's radius, apothem and half of the hexagon's side. Since the apothem forms a right angle with the hexagon's side and since the hexagon's side forms 60∘ with a circle's radius with an endpoint in common with the hexagon's side, we can determine the side in this fashion:

tan60∘=opposed cathetusadjacent cathetus => √3=Apothemside2 => side=(2√3)Apothem

As already mentioned the area of the regular hexagon is formed by the area of 6 equilateral triangles (for each of these triangle's the base is a hexagon's side and the apothem functions as height) or:

Shexagon=6⋅S△=6(base)(height)2=3(2√3)Apothem⋅Apothem=(6√3)(Apothem)2

=> Shexagon=6×62√3=216

8 0
3 years ago
John ordered a large three topping pizza for $7. 50 and a large 8 topping pizza for $10. Write an equation in slope-intercept fo
yKpoI14uk [10]

to get the equation of any straight line, we simply need two points off of it, well, let's use the provided values hmmm

\begin{array}{ccll} \stackrel{toppings}{x}&\stackrel{cost}{y}\\ \cline{1-2} 3 & 7.50\\ 8& 10 \end{array} \qquad\implies \qquad (\stackrel{x_1}{3}~,~\stackrel{y_1}{7.50})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{10}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{10}-\stackrel{y1}{7.50}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{3}}}\implies \cfrac{2.5}{5}\implies \cfrac{~~ \frac{25}{10}~~}{5}\implies \cfrac{25}{50}\implies \cfrac{1}{2}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7.50}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{3})\implies y-\cfrac{750}{100}=\cfrac{1}{2}(x-3) \\\\\\ y-\cfrac{15}{2}=\cfrac{1}{2}x-\cfrac{3}{2}\implies y=\cfrac{1}{2}x-\cfrac{3}{2}+\cfrac{15}{2}\implies y=\cfrac{1}{2}x-6

3 0
2 years ago
Walter asks to borrow $5 from Sharon on Monday, and another $8 on Tuesday. If he pays back $6 on Wednesday and borrows another $
Vera_Pavlovna [14]

Answer:

$12 is owed

Step-by-step explanation:

5 + 5 + 8 = 18

18 - 6 = 12

4 0
3 years ago
What is the nth term rule of the quadratic sequence below?
ludmilkaskok [199]
The answer is a multiple of + 4 for each number resting
4 0
3 years ago
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