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3 years ago

If a number is a natural number it is a complex number

1 answer:

4 0

The answer to this is yes. Natural numbers are a subset of the integers which are a subset of the reals which are complex numbers. A complex number can also be written as a+bi, which a real number has imaginary part 0, so just a. An integer is a number that can be written without a fractional or decimal component, and a natural number is an integer that is at least 0. Either way, a natural number is a complex number.

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When charles randomly chooses a fruit from a basket of apples and oranges, the odds are 5 to 3 that he will select an orange. wh

Naily [24]

0 bc 5 to 3 =543 chances 0 unlikely

7 0

3 years ago

A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3>Solution:</h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

The area of rectangle is given as:

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

General form of quadratic equation is

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0

3 years ago

Solve the expression (7th grade math): -0.8m+3-12.5m+95.36m

Lana71 [14]

Step-by-step explanation:

Combine Like-Terms:

-0.8m + 3 - 12.5m + 95.36m

-13.3m + 3 + 95.36m

82.06m + 3

82.06m + 3 is your simplified expression.

7 0

2 years ago

HELP PLEASSEEE IT REALLY URGENT!!!! PLEASE ONLY ANSWER IF YOU ARE CONFIDENT!

Dmitry [639]

Answer:

B. 12.5 feet below the surface of the water

Step-by-step explanation:

-20 + (-32.5) + 40

40 - 52.5

= -12.5 feet

= 12.5 feet below the water

6 0

2 years ago

A gardener is planting two types of trees:

nordsb [41]

2x+9=6x+7. 2x+2=6x. 2=4x. X=1/2 a year

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3 years ago