Answer:
T=138 °C
Explanation:
Given that
m = 0.028 kg
Net work output W= 60 KJ
T₂=2T₁
As we know that efficiency of Carnot heat engine given as
η = 0.5
We know that
Qa=heat addition
W= net work output
Qa= 120 KJ
From first law
Qa= W+ Qr
Qr= 120 - 60
Qr= 60 KJ
Qr Is the heat rejection.
Heat rejection per unit mass
Qr=60 / 0.028 = 2142.85 KJ/kg
Qr= 2142.85 KJ/kg
Temperature at which latent heat of steam is 2142.85 KJ/kg will be our answer.
T=138 °C
The temperature corresponding to 2142.85 KJ/kg will be 138 °C.
T=138 °C
Answer:
shoe box covered in aluminum foil
Answer:
Given
The normal strain in x -direction is defined as
Similarly the normal strain in y-direction is defined as
Now since there is no displacement field along y direction thus we have
Similarly shear strain in xy plane is given by
Answer:
t= 0.75 s
Explanation:
Here given that there is no any external torque that is why it angular momentum will be conserve.
Initial angular momentum= m V₁ r₁
Final angular momentum= m V₂ r₂
So
m V₁ r₁ = m V₂ r₂
Now by putting the values
m V₁ r₁ = m V₂ r₂
V₁ r₁ = V₂ r₂
6 x 3 = 12 x r₂
r₂ = 1.5 ft
So the time t
t = r₂ / Vr
t= 1.5 / 2
t= 0.75 s