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stira [4]
3 years ago
13

Jack has been concerned about the rapidly changing green regulations in his state and his ability as a mechanical engineer to ke

ep up with developments in his field relating to green requirements. He wants to talk to his boss about taking a professional sabbatical to increase his knowledge of green mechanical engineering practices. How do you predict Jack will try to convince his boss to agree? (Select all that apply.)
a. Identify how greater knowledge of green mechanical engineering areas, such as robotics or waste management, could extend the company’s service offerings.

b. Explain how a better knowledge of integrated mechanical systems could help the company provide more energy-efficient options to customers.

c. Describe how a smarter selection of more efficient, forward-thinking equipment could help the company’s bottom line.

d. Warn that with regulations and green technology changing so fast, the potential for poor implementation and mistakes is large
Engineering
1 answer:
uysha [10]3 years ago
3 0

Answer:

Option A, B and D

Explanation:

Jack can easily convince boss if he focus around two major aspects of the company

a) Revenue enhancement - Jack must outline the benefits of his research that can be used to improvise customer offerings and  hence can be further used to devise more energy-efficient options to customer

b) Reduction in mistakes - Issues such as poor implementation can be avoided with better approach and understanding.

Hence, option A, B and D are correct

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In c the square root of a number N can be approximated by repeated calculation using the formula NG = 0.5(LG + N/LG) where NG st
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Answer:

Following are the program to the given question:

#include <stdio.h>//header file

double square_root(double N, double initialGuess)//defining a method square_root that takes two variable in parameters

{

double NG, LG = initialGuess,diff;//defining double variable

while(1)//use loop to calculate square root value

{

NG = 0.5 * (LG + N / LG);//using given formula

diff = NG - LG;//calculating difference

if(diff < 0)//use if to check difference is less than 0

diff = -diff;//decreaing difference

if(diff < 0.005)//use if that check difference is less than 0.005

break;//using break keyword  

else//defining else block

{

LG = NG;//holding value

}

}

return NG;//return value

}

int main()//defining main method

{

double ans, n,initialguess = 1.0;//defining double variable

n = 4;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 120.5;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 36.01;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

n = 0.25;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

printf("\nEnter a number: ");//print message

scanf("%lf", &n);//input value

ans = square_root(n, initialguess);//calculating the square root value and print its value

printf("square_root(%lf) = %lf \n", n, ans);//print calculated value with number

}

Output:

Please find the attachment file.

Explanation:

  • In this code, a method "square_root" is declared that takes two variable "N, initialGuess" in its parameters, inside the method a three double variable is declared.
  • It uses the given formula and uses the diff variable to hold its value and uses two if to check its value is less than 0 and 0.005 and return its calculated value.
  • In the main method, three double variables are declared that use the "n" to hold value and "ans" to call the method that holds its value and print its value.

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