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aalyn [17]
3 years ago
8

On a farm the number of cows and the number of sheep are in the tatio 6:5 the number of sheep and the number of pigs are in the

ratio 2:1 the total number is 189 how many sheep are there on the farm?
Mathematics
1 answer:
Rzqust [24]3 years ago
8 0

Answer:

There are 70 sheep in the farm.

Step-by-step explanation:

Consider the provided information.

Let c represents the cows, s represents the sheep and p represents the pigs.

The number of cows and the number of sheep are in the ratio 6:5.

\dfrac{c}{s} =\dfrac{6}{5}

c =\dfrac{6s}{5}

The number of sheep and the number of pigs are in the ratio 2:1.

\dfrac{s}{p} =\dfrac{2}{1}

p =\dfrac{s}{2}

The total number is 189.

c+s+p=189

Substitute the value of c and p in above.

\dfrac{6s}{5}+s+\dfrac{s}{2}=189

\dfrac{12s+10s+5s}{10}=189

27s=1890

s=70

Hence, there are 70 sheep in the farm.

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A square piece of fabric is the side length of 3.2 cm find the area of the piece of the fabric
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The area of square fabric piece is 10.24 cm^2

Step-by-step explanation:

Square is a four-sided shape where all sides are equal. The area of square is calculated by using its side.

Given

Side length of fabric piece = s = 3.2 cm

The area of square is given by:

Area = A = s^2

Putting s= 3.2

Area = (3.2)^2\\= 10.24\ cm^2

Hence,

The area of square fabric piece is 10.24 cm^2

Keywords: Square, area

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What is 24/10 simplified
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98, 64, 75, 57, 86, 60, 91, 98, 79
astraxan [27]

Answer:

The median is 79

The median of the first quartile is 62

The median of the third quartile is 94.5

The inter quartile range is 32.5

Step-by-step explanation:

The median is the middle number of arranged number from smallest to greatest

The median of the first quartile is the middle number of the numbers before the median

The median of the third quartile is the middle number of the numbers after the median

The inter quartile range is the difference of the median of the 3rd quartile and the median of the 1st quartile

The numbers are 98, 64, 75, 57, 86, 60, 91, 98, 79

Let us arrange the numbers from small to big

57, 60, 64, 75, 79, 86, 91, 98, 98

They are 9 numbers

The middle one is the 5th number (4 before it and 4 after it)

The 5th number is 79

The median is 79

The numbers before the median are 57, 60, 64, 75

They are 4 numbers

The middle numbers are 2nd and 3rd

The median is the average of them

The 2nd number is 60 and the 3rd number is 64

The median of the first quartile = \frac{60+64}{2} = 62

The median of the first quartile is 62

The numbers before the median are 86, 91, 98, 98

They are 4 numbers

The middle numbers are 2nd and 3rd

The median is the average of them

The 2nd number is 91 and the 3rd number is 98

The median of the third quartile = \frac{91+98}{2} = 94.5

The median of the third quartile is 94.5

The inter quartile range = third median - first median

First median = 62

Third median = 94.5

Inter quartile range = 94.5 - 62 = 32.5

The inter quartile range is 32.5

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3 years ago
Whats the correct answer?
strojnjashka [21]

Answer:

its the 4 one

Step-by-step explanation:

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