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lara31 [8.8K]
3 years ago
12

I need to know how to round to the nearest hundredth in the number 1.120

Mathematics
2 answers:
user100 [1]3 years ago
7 0
The answer would be 1.12
Marta_Voda [28]3 years ago
3 0
You would do that by looking at the hundredths place.
1 is whole next 1 is tenths 2 is hundredths.
Is it 0 1 2 3 4 or 5 6 7 8 9?
If it is 0 1 2 3 4 you would turn it into a 0.
If it was 5 6 7 8 9 it would make the tenths go up +1 and the hundredths and thousandths places 0. 
So it would be 1.100


























































































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What would be the answer please explain
sp2606 [1]

Using the line of the best fit, the predicted student's score in English test is 48

<h3>How to determine the student's score in English?</h3>

From the question, we have:

Mathematics score = 60

The scores in English tests are plotted on the y-axis.

On the given graph, we have:

(x,y) = (60,48)

This means that when x = 60, the value of y is 48

This in other words means that the student's score in English test is 48

Read more about line of best fit at:

brainly.com/question/17261411

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6 0
2 years ago
Complete the following statement with the number that makes it true.
ANEK [815]

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so answer is 1000

8 0
4 years ago
The length of a rectangle is three more than twice the width. The perimeter is 96. What are the dimensions? ​
SIZIF [17.4K]

Answer:

Width =15

Length =33

Step-by-step explanation:

Take width as x

And length as 2x+3

Perimeter as 96

Formula of the perimeter of a rectangle is 2l+2w

X+×+2×+3+2×+3=96

6x+6=96

6x=96-6

6×=90

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Width =x and x =15 so width =15 while length =33

7 0
3 years ago
Hi, can someone please help, and possibly explain the answer please.
mr_godi [17]

Answer:

x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

Step-by-step explanation:

Quadratic formula: x=\frac{-b\±\sqrt{b^2-4ac} }{2a} when the equation is 0=ax^2+bx+c

The given equation is 1=-2x+3x^2+1. Let's first arrange this so its format looks like y=ax^2+bx+c:

1=-2x+3x^2+1

1=3x^2-2x+1

Subtract 1 from both sides of the equation

1-1=3x^2-2x+1-1\\0=3x^2-2x+0

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

I hope this helps!  

8 0
3 years ago
Find the area of the rectangle:
kumpel [21]
10 ft and 2 because I did the math
6 0
3 years ago
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