What are the zeros of the function below? check all that apply

Some help me please i have 9 questions

Lyrx [107]

awnser:

m<3=50

Step-by-step explanation:

seen in the picture if you need help let me know

5 0

3 years ago

Can anyone please answer number 6.

xeze [42]

Answer:

Step-by-step explanation:

Exact Form:

2

√

2

+

3

√

5

−

2

+

3

5

-

2

Decimal Form:

7.53663105

…

7 0

3 years ago

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A hospital employs a total of 77 nurses and doctors. The ration if nurses to doctors is 9:2. How many nurses are employed at the

exis [7]

Answer: 63 nurses and 14 doctors

so you know the ratio is 9:2. that means for every 9 nurses there are 2 doctors. i didn't make an equation but i counted it.

if theres 9 (9*1) nurses theres 2 (2*1) doctors

if theres 18 (9*2) nurses theres 4 (2*2) doctors

if theres 27 (9*3) nurses theres 6 (2*3) doctors

you get the point so i multiplied 7 to 9 and 7 to 2, which means:

if theres 63 (9*7) nurses theres 14 (2*7) doctors

i hope this helps :)

6 0

3 years ago

Find the area ratio of a regular octahedron and a tetrahedron regular, knowing that the diagonal of the octahedron is equal to h

Anton [14]

Answer:

$\frac{4}{3}$

Step-by-step explanation:

The area of a regular octahedron is given by:

area = $2\sqrt{3}\ *edge^2$ . Let a is the length of the edge (diagonal).

area = $2\sqrt{3}\ *a^2$

Given that the diagonal of the octahedron is equal to height (h) of the tetrahedron i.e.

a = h, where h is the height of the tetrahedron and a is the diagonal of the octahedron. Let the edge of the tetrrahedron be e. To find the edge of the tetrahedron, we use:

$h=\sqrt{\frac{2}{3} } e\\but\ h=a\\a=\sqrt{\frac{2}{3} } e\\e=\sqrt{\frac{3}{2} }a$

The area of a tetrahedron is given by:

area = $\sqrt{3}\ *edge^2$ = $\sqrt{3} *(\sqrt{\frac{3}{2} }a)^2=\frac{3}{2}\sqrt{3} *a^2$

The ratio of area of regular octahedron to area tetrahedron regular is given as:

Ratio = $\frac{2\sqrt{3}\ *a^2}{\frac{3}{2} \sqrt{3}*a^2} =\frac{4}{3}$

7 0

3 years ago

50 points plus brainliest please help screenshot provided

never [62]

Answer:

$\textsf{(a)} \quad (3x)^{\circ}+(x+14)^{\circ}=90^{\circ}$

$\textsf{(b)} \quad m \angle 1=\boxed{57}\:^{\circ}$

$m \angle 2=\boxed{33}\:^{\circ}$

Step-by-step explanation:

From inspection of the given diagram:

$m \angle 1=(3x)^{\circ}$

$m \angle 2=(x+14)^{\circ}$

A right angle is 90° and is represented by the ∟ symbol.

To find x, <u>equal</u> the sum of the angles to 90° and solve for x:

$\implies m \angle 1+m\angle2=90^{\circ}$

$\implies (3x)^{\circ}+(x+14)^{\circ}=90^{\circ}$

$\implies 3x+x+14=90$

$\implies 4x+14=90$

$\implies 4x+14-14=90-14$

$\implies 4x=76$

$\implies 4x \div 4=76 \div 4$

$\implies x=19$

To find the degree measure of each angle, substitute the found value of x into the expression for each angle.

$\implies m \angle 1=(3 \cdot 19)^{\circ}=57^{\circ}$

$\implies m \angle 2=(19+14)^{\circ}=33^{\circ}$

6 0

1 year ago

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