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Mice21 [21]
3 years ago
8

Match the terms to their definition. 1. dispersion a data value that is far from the others 2. inter-quartile range how data is

distributed 3. lower quartile the difference between the largest and smallest of the middle 50% of the data set 4. outlier the median of the lower half of the data set; a value which 25% of the data set falls below 5. percentile the median of the upper half of the data set; a value which 75% of the data set falls below 6. range a value below which a certain percentage of the data set falls; the median is the 50th percentile 7. upper quartile the difference between the largest and smallest of the numbers in a set
Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

1. Dispersion: how data is distributed

2. Inter quartile range:the difference between the largest and smallest of the middle 50% of the data set

3. Lower Quartile:the median of the lower half of the data set; a value which 25% of the data set falls below

4. Outlier:a data value that is far from the others

5. Percentile: a value below which a certain percentage of the data set falls; the median is the 50th percentile.

6. Range:the difference between the largest and smallest of the numbers in a set

7. Upper Quartile:the median of the upper half of the data set; a value which 75% of the data set falls below

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The bottom and top of a box are rectangles twice as long as they are wide. Find the volume of the box if it is four feet high an
Sav [38]

Let x = the width

then

2x = the length

:

The box dimensions: 2x by x by 4

Given the surface area:

2(2x*x) + 2(2x*4) + 2(x*4) = 220

:

4x^2 + 16x + 8x = 220


A quadratic equation:

4x^2 + 24x - 220 = 0

simplify, divide by 4

x^2 + 6x - 55 = 0

Factor

(x+11)(x-5) = 0

The positive solution is what we want here:

x = 5 ft is the width

then

2(5) = 10 ft is the length

:

Find the volume

10 * 5 * 4 = 200 cu/ft is the volume


5 0
2 years ago
Help I need sleep and I live in Canada, de las ovejas and it's 1am
MrMuchimi

Answer:

Answer:

The student council made more snow cones per hour than the parent volunteers.

Explanation:

To find the number of snow cones made per hour:

XXX

Divide the number of snow cones made

XXX

by the number of hours spent making snow cones.

Parent volunteers

XXX

Number of snow cones:  

120

XXX

Number of hours spent making snow cones:  

5

Number of snow cones per hour:  

120

÷

5

=

24

Student council

XXX

Number of snow cones:  

100

XXX

Number of hours spent making snow cones:  

4

Number of snow cones per hour:  

100

÷

4

=

25

Since the student council made  

25

snow cones per hour and the parent volunteers only made  

24

snow cones per hour:

the student council made more snow cones per hour.

Step-by-step explanation:


4 0
3 years ago
Suppose the average tread-life of a certain brand of tire is 42,000 miles and that this mileage follows the exponential probabil
Ahat [919]

Answer: The probability that a randomly selected tire will have a tread-life of less than 65,000 miles is 0.7872 .

Step-by-step explanation:

The cumulative distribution function for exponential distribution is :-

P(X\leq x)=1-e^{\frac{-x}{\lambda}}, where \lambda is the mean of the distribution.

As per given , we have

Average tread-life of a certain brand of tire :  \lambda=\text{42,000 miles }

Now , the probability that a randomly selected tire will have a tread-life of less than 65,000 miles will be :

P(X\leq 65000)=1-e^{\frac{-65000}{42000}}\\\\=1-e^{-1.54761}\\\\=1-0.212755853158\\\\=0.787244146842\approx0.7872

Hence , the probability that a randomly selected tire will have a tread-life of less than 65,000 miles is 0.7872 .

8 0
3 years ago
An auto dealership sells minivans and sedans. In January, they sold 10 minivans and 20 sedans. In February, they sold 7 minivans
zaharov [31]

Answer:

january = 10/20 = 1/2

februry = 7/14 = 1/2

so, we conclude that the auto dealership didn't have a lower ratio, since the ratio is equal in both months.

<em>hope it helps :)</em>

<em />

8 0
2 years ago
HELP URGENT BRAINLIEST
nadya68 [22]

Given:

LMN is an equilateral triangle.

LM = LN = MN = 12 cm

To find:

The height of the triangle h.

Solution:

In a right angle triangle,

\sin \theta=\dfrac{Opposite}{Hypotenuse}

\sin (60^\circ)=\dfrac{h}{12}

\dfrac{\sqrt{3}}{2}=\dfrac{h}{12}

Multiply both sides by 12.

\dfrac{\sqrt{3}}{2}\times 12=\dfrac{h}{12}\times 12

6\sqrt{3}=h

Therefore, the height of the triangle is 6\sqrt{3} cm.

3 0
2 years ago
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