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kotegsom [21]
3 years ago
12

Solve for the variable

Mathematics
1 answer:
krek1111 [17]3 years ago
5 0

Answer:

G = 2/3

Step-by-step explanation:

-13G + 10 = 2(-5G + 4)  Distribute the 2 to (-5G + 4)

-13G + 10 = -10G + 8  

+13G           +13G         Add 13G to both sides

10 = 3G + 8

-8           -8                  Subtract 8 from both sides

2 = 3G                          Divide both sides by 3

2/3 = G

If this answer is correct, please make me Brainliest!

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the profit for a taco truck business follows this function, where x is the price of a taco(in dollars) and y is the daily profit
Sati [7]

Answer:

x = √2 + 2, -√2 + 2

Step-by-step explanation:

y = -2(x-2)² + 4

-2(x-2)² + 4 = 0 --- replace y with 0

-2(x - 2)² = -4 --- subtract 4 from both sides

(x - 2)² = \frac{-4}{-2} --- divide both sides by -2

(x - 2)² = 2 --- simplify

x - 2 = +-√2 --- square root both sides

x - 2 = √2 --- split into 2 equations

x - 2 = -√2

x = √2 + 2 --- solve first equation

x = -√2 + 2 --- solve second equation

x = √2 + 2, -√2 + 2


4 0
3 years ago
Read 2 more answers
PLS HELP ME XD, WHAT IS 1/4 x 24??
Shkiper50 [21]
1/4 x 24 is 6.

Your welcome
8 0
3 years ago
3 friends' meals at a resuraunt cost $13 $14 and $11. Use perentheses to write two diffrent expressions to show how much they sp
klemol [59]

Answer:

38

Step-by-step explanation:

(11+13)+14

11+13=24

24+14=38

8 0
3 years ago
Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A
alekssr [168]

Answer:

\theta_{CAB}=128.316

\theta_{ABC}=25.842

\theta_{BCA}=25.842

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}

AB= \sqrt{(-3-1)^2+(0-3)^2}=5

BC= \sqrt{(1-1)^2+(3-(-3))^2}=9

CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}

\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}

\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}

\theta_{CAB}=\arccos{-\dfrac{0.62}}

\theta_{CAB}=128.316

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}

\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)

\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)

\theta_{ABC}=\arcsin{0.4359}\right)

\theta_{ABC}=25.842

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

\theta_{BCA}=25.842

this can also be checked using the fact the sum of all angles inside a triangle is 180

\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180

25.842+128.316+25.842

180

6 0
3 years ago
Read 2 more answers
Can someone help me solve parts (a) and (c) please? Thank you!
Brilliant_brown [7]

a) 4x +6

Add up all the sides to calculate perimeter

6 0
3 years ago
Read 2 more answers
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