- 133 > -7(2x+3)
-133 > -14x - 21
-133 + 21 > -14x
-112 > -14x │ × (-1)
112 < 14x
14x > 112
x > 112/14
x > 8
The length of ST to the nearest tenth of a foot is 5.2 ft
Step-by-step explanation:
Here we have
∡T = 90°
∡R = 64°
RS = 5.8 ft
To answer the question, we have apply sine rule as follows;
Therefore, for triangle RST, we will have;
Therefore;
from which
Therefore, the length of ST to the nearest tenth of a foot = 5.2 ft.
Answer:
Step-by-step explanation:
Radius = r = 9 cm
Angle = θ = 200° = 3.5 radians
Now,
Area = 1/2 (9)²(3.5)
Area = 1/2 (81)(3.5)
Area = 282.7 / 2
Area of sector = 141.4 cm²
Answer:
The area of the square adjacent to the third side of the triangle is 11 units²
Step-by-step explanation:
We are given the area of two squares, one being 33 units² the other 44 units². A square is present with all sides being equal, and hence the length of the square present with an area of 33 units² say, should be x² = 33 - if x = the length of one side. Let's make it so that this side belongs to the side of the triangle, to our convenience,
x² = 33,
x = 
.... this is the length of the square, but also a leg of the triangle. Let's calculate the length of the square present with an area of 44 units². This would also be the hypotenuse of the triangle.
x² = 44,
x = 
.... applying pythagorean theorem we should receive the length of a side of the unknown square area. By taking this length to the power of two, we can calculate the square's area, and hence get our solution.
Let x = the length of the side of the unknown square's area -
= 
+ 
,
x = 
... And squared is 11, making the area of this square 11 units².
