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Svetlanka [38]
3 years ago
15

If two lines intersect, then they intersect in exactly one _____ point. line. postulate. plane.

Mathematics
1 answer:
Rom4ik [11]3 years ago
6 0

Answer: the answer is A. point

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This is a square pyramid. What is the length of the base? h=3 v=36
Ulleksa [173]

volume of square pyramid = S^2*h/3

volume = 36

 h = 3

36 = S^2 *3/3

36 = S^2

S = sqrt(36)

S = 6

length of base = 6

7 0
3 years ago
A hair care company makes three batches of scented shampoo using the recipe shown. Each batch contains a different total amount
Nostrana [21]

i think there is 5 total units in the shampoo; 2 1/2 units of pineapple; 1/5(5) = 1 unit of banana; and 3/10(5) = 1 1/2 units of coconut. im not fully sure

so if im wrong correct me but have a blessed day/night

=)

4 0
3 years ago
What is the length of the radius of a cylinder if the diagonal is 15 mm and the height is 12 mm?
Anestetic [448]

Answer:

Step-by-step explanation:

Let d and r be the diameter and radius, respectively.

d² + 12² = 15²

d² = 15² - 12² = 81

d = √81 = 9

r = d÷2 = 4.5 mm

4 0
3 years ago
You have a fishing line spool with an end that has an area of 20.0 cm2. how much fishing line do you need to wind around the spo
grandymaker [24]

Answer: 158.53 cm

Step-by-step explanation:

We know that the ends of a fishing line spool are circular in shape.

Given : The area of an end of fishing line spool = 20.0\cm^2   (1)

Area of a circle = \pi r^2                                (2)

Circumference of a circle = 2\pi r                           (3)

, where r is radius of the circle.

From (1) and (2), we have

\pi r^2=20\\\\\Rightarrow\ r^2=\dfrac{20}{\pi}\\\\\Rightarrow\ r=\sqrt{\dfrac{20}{\pi}}                

Circumference of fishing spool = 2\pi r               (using (3))

=2\pi \sqrt{\dfrac{20}{\pi}}=2\sqrt{20\pi}=2\times2\sqrt{5\pi}=4\sqrt{5\pi}

i.e. Fishing spool required to wind around the spool one time =4\sqrt{5\pi}\ cm

⇒ Fishing spool required to wind around the spool 10 times =10\times4\sqrt{5\pi}\ cm=40\sqrt{5\pi}\\\\=40\times\sqrt{5}\times \pi\\\\=40\times2.236\times\sqrt{3.14159}\\\\=89.44\times1.772453\\\\=158.528205473\approx158.53\ cm

Hence, you need 158.53 cm or about 159 cm of fishing line to wind around the spool 10 times.

7 0
3 years ago
Solve each inequality <br><br> 10 |5n-5| =50
V125BC [204]
10|5n-5|=50  divide both sides by 10

|5n-5|=5 square both sides:

25n^2-50n+25=25  subtract 25 from both sides

25n^2-50n=0  factor...

25n(n-2)=0

So n=0 and 2
5 0
3 years ago
Read 2 more answers
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