Mean = 26.75
Range = 25
The answer is C!
Subtract the constant vector that is on the left. The arithmetic applies to corresponding elements of the vectors.
![A=\left[\begin{array}{cccc}0&1&-2&3\end{array}\right] -\left[\begin{array}{cccc}11&17&-8&13\end{array}\right]\\\\A=\left[\begin{array}{cccc}-11&-16&6&-10\end{array}\right]\\\\a_{11}=-11\\a_{12}=-16\\a_{13}=6\\a_{14}=-10](https://tex.z-dn.net/?f=%20A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D0%261%26-2%263%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D11%2617%26-8%2613%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CA%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-11%26-16%266%26-10%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5Ca_%7B11%7D%3D-11%5C%5Ca_%7B12%7D%3D-16%5C%5Ca_%7B13%7D%3D6%5C%5Ca_%7B14%7D%3D-10%20)
Another way to name one forth is to say that he coloured a quarter of the rectangle because a quarter is one forth
hope that helps
Answer:
probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = 0.001932
Step-by-step explanation:
P(BAC=0|Crash with fatality)=0.625
P(BAC is between .01 and .09|Crash with fatality)=0.302
P(BAC is greater than .09|Crash with fatality)=0.069
Let the event of BAC = 0 be X
Let the event of BAC between 0.01 and 0.09 be Y
Let the event of BAC greater than 0.09 be Z
Let the event of a crash with at least one fatality = C
P(X|C) = 0.625
P(Y|C) = 0.302
P(Z|C) = 0.069
P(C) = 0.028
probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = P(C n Z)
But note that the conditional probability of probability that a driver is intoxicated (BAC greater than 0.09) given that there was a crash that involved at least a fatality is given by
P(Z|C) = P(Z n C)/P(C)
P(Z n C) = P(Z|C) × P(C) = 0.069 × 0.028 = 0.001932
Hope this Helps!!!
Answer:
see explanation
Step-by-step explanation:
Sum the sides of both polygons and equate.
(20)
x + 4 + x + 2 + x + 5 = 2(x + 1) + 2(x + 3) ← distribute parenthesis
3x + 11 = 2x + 2 + 2x + 6
3x + 11 = 4x + 8 ( subtract 3x from both sides )
11 = x + 8 ( subtract 8 from both sides )
3 = x
(21)
5(12x) = x + 7 + 6x + 9 + x + 10
60x = 8x + 26 ( subtract 8x from both sides )
52x = 26 ( divide both sides by 52 )
x = 
= 
