√2, √3, √5, √11, √21, π(Pi) are all irrational.
1. First, let us define the width of the rectangle as w and the length as l.
2. Now, given that the length of the rectangle is 6 in. more than the width, we can write this out as:
l = w + 6
3. The formula for the perimeter of a rectangle is P = 2w + 2l. We know that the perimeter of the rectangle in the problem is 24 in. so we can rewrite this as:
24 = 2w + 2l
4. Given that we know that l = w + 6, we can substitute this into the formula for the perimeter above so that we will have only one variable to solve for. Thus:
24 = 2w + 2l
if l = w + 6, then: 24 = 2w + 2(w + 6)
24 = 2w + 2w + 12 (Expand 2(w + 6) )
24 = 4w + 12
12 = 4w (Subtract 12 from each side)
w = 12/4 (Divide each side by 4)
w = 3 in.
5. Now that we know that the width is 3 in., we can substitute this into our formula for length that we found in 2. :
l = w + 6
l = 3 + 6
l = 9 in.
6. Therefor the rectangle has a width of 3 in. and a length of 9 in.
Split this figure into 3 shapes: 2 triangles and 1 trapezoid
Area of top triangle = 1/2(7)(2) = 7 square units
Area of bottom triangle = 1/2(3)(7) = 10.5 square units
Area of trapezoid = 1/2(3 + 6)(4) = 18 square units
Area of the polygon = 7 + 10.5 + 18 = 35.5 square units
V = 24/3 = 8
So v = 8
Hope this helps, if it is , pls brainliest !!
The answer to this question is A. 12
