Layla has the following data:

1 answer:

6 0

The answer would be 25 because to find the range you have to subtract the highest number with the lowest number which would be 29-25=4

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How much of the circle is shaded 1/4+3/7

Snezhnost [94]

I hope this helps you

1/4+3/7

7/7.4+3.4/7.4

7/28+12/28

19/28

4 0

3 years ago

0647grams nearest tenth

balu736 [363]

1000 is the answer! hoped I helped

8 0

3 years ago

Use the properties of logarithms to expand the following expression as much as possible. Simplify any numerical expressions that

sweet [91]

Answer:

$f(x,y) = \log_{4} (x-5-\sqrt{25-6\cdot y})+\log_{4} (x-5+\sqrt{25-6\cdot y})$

Step-by-step explanation:

Let be $f(x,y) = \log_{4}(2\cdot x^{2}-20\cdot x +12\cdot y)$ , this expression is simplified by algebraic and trascendental means. As first step, the second order polynomial is simplified. Its roots are determined by the Quadratic Formula, that is to say:

$r_{1,2} = \frac{20\pm \sqrt{(-20)^{2}-4\cdot (2)\cdot (12\cdot y)}}{2\cdot (2)}$

$r_{1,2} = 5\pm \sqrt{25-6\cdot y}$

The polynomial in factorized form is:

$(x-5-\sqrt{25-6\cdot y})\cdot (x-5+\sqrt{25-6\cdot y})$

The function can be rewritten and simplified as follows:

$f(x,y) = \log_{4} [(x-5-\sqrt{25-6\cdot y})\cdot (x-5+\sqrt{25-6\cdot y})]$

$f(x,y) = \log_{4} (x-5-\sqrt{25-6\cdot y})+\log_{4} (x-5+\sqrt{25-6\cdot y})$

3 0

3 years ago

One thousand grams is <br> A) 1 milligram <br> B) 1 centigram <br> C) 1 hectogram <br> D) 1 kilogram

kirill [66]

1,000 grams = 1 kilogram

Hopefully I was helpful.

7 0

3 years ago

Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation

just olya [345]

Answer:

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation $v(t)= 6t^2-18t+12$ . We are asked to find the distance that the particle will travel in its first 2 seconds.