Mei is writing a coordinate proof involving a right isosceles triangle. Mei places her triangle on the coordinate plane such tha
t one of the legs of the triangle lies along the x-axis and the other leg is parallel to the y-axis.
~ What coordinates should she assign to this third vertex of the right isosceles triangle?
~ What coordinates should she assign to this third vertex of the right isosceles triangle?
2 answers:
Answer: (a,a)
Step-by-step explanation:
Given: A right isosceles triangle which is placed on the coordinate plane such that one of the legs of the triangle lies along the x-axis and the other leg is parallel to the y-axis.
From the given figure one vertex is on origin(0,0) and second on x -axis as (a,0) .ii.e. one side of the triangle is on the x axis with length 'a' and the side parallel to the y axis should perpendicular to the x axis with length 'a'.(∵ two sides are equal in a right isosceles triangle)
So the coordinates should she assign to the third vertex of the right isosceles triangle is (a,a).[as the point lie above the point (a,0), so its x abscissa should be same]
You might be interested in
The value of gf(5) for the given two expressions is 135.
According to the question,
We have the following information:
f(x)= x +4
g(x) = 3x
Now, in order to find the value of gf(5), we will first find the value of gf.
Now, we will multiply these two expressions:
3x(x+4)
Now, the terms outside the brackets need to multiplied inside the bracket:
Now, we will put the value of x in this expression as 5 and solve the expression further by multiplication and addition:
3*5*5+12*5
75+60
135
Hence, the value of gf(5) for the given two expressions of f(x) and g(x) is 135.
To know more about value here
#SPJ1