Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Expanded form:
1 × 100,000,000
+ 5 × 10,000,000
+ 4 × 1,000,000
+ 7 × 100,000
+ 9 × 10,000
+ 8 × 1,000
+ 1 × 100
+ 0 × 10
+ 5 × 1
I hope it helps :)
Answer:
0.06245
Step-by-step explanation:
Decrease 7/12=0.583
from 9 p.m to 6:20 am is 9:20= (9+20/60) = 9.33 hours
0.583/9.33 = 0.06248
round the 0.06248 to 0.06245
The answer is the last one 5x-12/(x+3)(x-3)
