You would plug in 6 where the x is so it would be -4 times 2 plus 5(6)
Answer:
Answer is A
Step-by-step explanation:
(14x^4y^6)/(7x^8y^2)
because everything is one term, you can split into three terms
14/7, x^4 / x^8 , and y^6/y^2
multiplying these three terms will get us the starting term
14/7 = 2
x^4 / x^8
with division of exponents, you subtract the smaller exponent (4), from the big exponent (8), and leave it on the same side (bottom) as the big exponent
1/x^4
same thing with our y's
y^6/y^2
this time, the term stays on the top
y^4
take the simplified terms and multiply them together
(2) * (1/x^4) * (y^4) =
A: (2y^4) / (x^4)
17 I think so ye how is a triangle a triangle is it’s half a square?
Part A
<h3>Answer:
h^2 + 4h</h3>
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Explanation:
We multiply the length and height to get the area
area = (length)*(height)
area = (h+4)*(h)
area = h(h+4)
area = h^2 + 4h .... apply the distributive property
The units for the area are in square inches.
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Part B
<h3>Answer:
h^2 + 16h + 60</h3>
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Explanation:
If we add a 3 inch frame along the border, then we're adding two copies of 3 inches along the bottom side. The h+4 along the bottom updates to h+4+3+3 = h+10 along the bottom.
Similarly, along the vertical side we'd have the h go to h+3+3 = h+6
The old rectangle that was h by h+4 is now h+6 by h+10
Multiply these expressions to find the area
area = length*width
area = (h+6)(h+10)
area = x(h+10) ..... replace h+6 with x
area = xh + 10x .... distribute
area = h( x ) + 10( x )
area = h( h+6 ) + 10( h+6 ) .... plug in x = h+6
area = h^2+6h + 10h+60 .... distribute again twice more
area = h^2 + 16h + 60
You can also use the box method or the FOIL rule as alternative routes to find the area.
The units for the area are in square inches.
A.) m=5/6
B.) y
=5/6x-3 use the slope formula y=mx+b
C.) y
-y1 = m(x-x1)
