Dilate the line segment AB with endpoints A(–3,1) and B(4,–2) about the origin with a scale factor 3. Find the endpoints of the
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Answer:
Perimeter of the board is 119.7 cm.
Step-by-step explanation:
We are given that,
Area of each square = 14 cm²
i.e.
i.e.
i.e Side = 3.74 cm
So, we get the side of each square is 3.74 cm.
Since, Perimeter of a square =
→ Perimeter of each square =
→ Perimeter of each square = 14.96 cm
<em>Since, there are 8×8= 64 squares on the board.</em>
Thus, the perimeter of the board = 8 × Perimeter of each square.
i.e. Perimeter of the board = 8 × 14.96
i.e. Perimeter of the board = 119.68 cm
Hence, the perimeter of the board rounded to the tenths is 119.7 cm.