Question

A checkers board is eight squares long and eight squares wide. The area of each square is 14 cm². Estimate the perimeter of the checkers board to the nearest 10th of a centimeter.

Answer 1

Answer:

Perimeter of the board is 119.7 cm.

Step-by-step explanation:

We are given that,

Area of each square = 14 cm²

i.e. $Side^2=14$

i.e. $Side= \sqrt{14}$

i.e Side = 3.74 cm

So, we get the side of each square is 3.74 cm.

Since, Perimeter of a square = $4a$

→ Perimeter of each square = $4\times 3.74$

→ Perimeter of each square = 14.96 cm

Since, there are 8×8= 64 squares on the board.

Thus, the perimeter of the board = 8 × Perimeter of each square.

i.e. Perimeter of the board = 8 × 14.96

i.e. Perimeter of the board = 119.68 cm

Hence, the perimeter of the board rounded to the tenths is 119.7 cm.