Ok so student in cleveland walks 2.5 miles away from cleveland every hour from 8
so the distance, x is x=2.5t
the riding one rides 4 hours later, so t-4
11 mph
y=11(t-4)
A. x=2.5t
y=11(t-4)
when do they meet is when the distance when they are equal or when x=y
2.5t=x=y=11(t-4)
solve for t
2.5t=11(t-4)
2.5t=11t-44
-8.5t=-44
divide both sides by -8.5
t=5.17647
answer is 5.18 hours
A.
x=2.5t
y=11(t-4)
B. 5.18 hours
Answer:
The answer to your question is x = 
or x = 5
Step-by-step explanation:
To solve this problem use the Pythagorean theorem because two right triangles are formed.
c² = a² + b²
c = 10
a = x
b = x Because in a square all the sides measure the same.
10² = x² + x²
- Simplify
100 = 2x²
x² = 100/2
x² = 50
x = or x = 5
Answer:
A) 2x*2 +6x -3x - 9= 2x*2 +3x -9
B) 2yx*2 +2yx +2y +3x*2 +3x +3
C) 36x*2 y +48yx +3xy*2 + 4y*2
D) 2x*3 - 4x*2 y + 3x -6y
Answer:
16
Step-by-step explanation:
Plug things in then use PEMDAS:
m * (7+9) * n
= 0.5 * (7+9) * 2
= 0.5 * 16 * 2
= 16
