The solution to the simplification of the algebraic expressions are;
A) 5p³q + 5pq³ + 5p²q
B) 14pqr² - 7p²qr
C) 20x² - 15xy - 16ax + 12ay
A) We have the expression;
5pq(p² + q² + pq)
Multiplying out using the concept of distributive property, we have;
(5pq × p²) + (5pq × q²) + (5pq × pq)
>> 5p³q + 5pq³ + 5p²q
B) We have the expression;
-7pr(pq – qr - rq)
Multiplying out using the concept of distributive property, we have;
-7p²qr + 7pqr² + 7pqr²
>> 14pqr² - 7p²qr
C) (4x - 3y)(5x - 4a)
By quadratic expansion, we have;
(4x * 5x) - (3y * 5x) - (4x * 4a) + (4a * 3y)
>> 20x² - 15xy - 16ax + 12ay
Read more about simplification of algebra at; brainly.com/question/4344214
Answer:
V≈17974.16
Step-by-step explanation:
Using the formulas
V=4
3πr3
d=2r
Solving for V
V=1/
6πd^3=1/
6·π·32.53≈17974.16422
Answer:
hello, i don't know what is answer, beacose im Ukrainian, sorry
To reduce this equation to lowest terms, we must first determine the factors of both the numerator and denominator. For the numerator, n^2-7n-144, the factors are (n-11) and (n+4). For the denominator, n2-121, the factors are (n-11) and (n+11). We can cancel out like terms, which is (n-11), leaving the lowest term (n+4)/(n+11).