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3 years ago

X+2=7 I={…-1,0,1,…} Answer:

Mathematics

1 answer:

Simora [160]3 years ago

3 0

Answer:

X = 5

Step-by-step explanation:

x + 2 = 7

- 2 = -2

0 5

x = 5

So x = 5. To check my work, we know that 5+2=7. Or 7-2=5

Hope this helps ☝️☝☝

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Angela tried to solve an equation step by step. \begin{aligned} \dfrac34+m&=\dfrac54\\\\ \dfrac34+m-\dfrac34&=\dfrac54+\

Liono4ka [1.6K]

Answer:

The mistake she made was ; She didn't change the sign when subtracting -3/4 from both sides

She wrote 5/4+3/4 instead of 5/4-3/4

Step-by-step explanation:

Correct solution:

$\frac{3}{4} + m = \frac{5}{4}$

Subtract-3/4 from both sides

$\frac{3}{4} - \frac{3}{4} + m = \frac{5}{4} - \frac{3}{4}$

Simplify

$m = \frac{5}{4} - \frac{3}{4} \\ m = \frac{1}{2}$

7 0

3 years ago

Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be

Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C' (C' = kC)

taking exponents of both sides, we have

$L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt} (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k} - \frac{C"}{k} e^{kt}$

When t = 0, A(0) = 0 (since the forest floor is initially clear)

$A = \frac{L}{k} - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k} - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k} - \frac{C"}{k} e^{0}\\\frac{L}{k} = \frac{C"}{k} \\C" = L$

$A = \frac{L}{k} - \frac{L}{k} e^{kt}$

So, D = R - A =

$D = \frac{L}{k} - \frac{L}{k} - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}$

when t = 0(at initial time), the initial value of D =

$D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}$

4 0

2 years ago

What the power a when 5^a = 1/125

Advocard [28]

Answer:

a = -3

General Formulas and Concepts:

Algebra I

Solving Exponential Equations

Exponential Property [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle 5^a = \frac{1}{125}$

Step 2: Solve for a

Rewrite: $\displaystyle 5^a = \frac{1}{5^3}$
Rewrite [Exponential Property - Rewrite]: $\displaystyle 5^a = 5^{-3}$
Set: $\displaystyle a = -3$

3 0

2 years ago

Find all the missing elements

Roman55 [17]

Answer:

$b = 5.5$

$c = 11.2$

Step-by-step explanation:

Given:

A = 96°

B = 25°

C = 59°

a = 13

Required:

b and c

SOLUTION:

Use Sine Rule to find the measure of a and b, respectively.

✍️Thus, to find b, use,

$\frac{a}{sin(A)} = \frac{b}{sin(B)}$

Plug in the values

$\frac{13}{sin(96)} = \frac{b}{sin(25)}$

Multiply both sides by sin(25)

$\frac{13}{sin(96)} \times sin(25) = \frac{b}{sin(25)} \times sin(25)$

$\frac{13 \times sin(25)}{sin(96)} = b$

$b = 5.5$ (nearest tenth)

✍️To find c, use,

$\frac{a}{sin(A)} = \frac{c}{sin(C)}$

Plug in the values

$\frac{13}{sin(96)} = \frac{c}{sin(59)}$

Multiply both sides by sin(59)

$\frac{13}{sin(96)} \times sin(59) = \frac{c}{sin(25)} \times sin(59)$

$\frac{13 \times sin(59)}{sin(96)} = c$

$c = 11.2$ (nearest tenth)

3 0

2 years ago

What does it mean when a equation has no solution?

velikii [3]

Hello!

No solutions means that there is two sides that do not equal or math, therefore, your answer would be c. both sides of the equation are not equal to one another.
Enjoy.

Brainliest please?

4 0

3 years ago

Read 2 more answers