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iVinArrow [24]
3 years ago
8

If the parabola of the form y = a(– h)^2 + k is always shifted horizontally h units and vertically k uni

Mathematics
1 answer:
quester [9]3 years ago
3 0

Answer:

im confused

Step-by-step explanation:

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Mario walked 7422 steps one day then he walks 5570 stops the next day. which calculation can be used to find the total number of
vovikov84 [41]

Answer:

A caucluation he can use is adding, just add 7422 and  5570 and you should get your answer.

Step-by-step explanation:

4 0
3 years ago
The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
astraxan [27]

Answer:

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

Step-by-step explanation:

In two similar triangles:

The ratio of the areas of two triangle is equal to the square of their perimeters.

Let A and A' represents the area of two triangles and P and P' represents their perimeter.

Then they are related as:

\dfrac{A}{A'}=\dfrac{P^2}{P'^2}

We are given:

A=72 dm^2  , A'=50 dm^2

and P+P'=226 dm.-----------(1)

i.e. \dfrac{72}{50}=\dfrac{P^2}{P'^2}\\\\\dfrac{36}{25}=\dfrac{P^2}{P'^2}

on taking square root on both the side we get:

\dfrac{P}{P'}=\dfrac{6}{5}\\\\P=\dfrac{6}{5}P'

Now putting the value of P in equation (1) we obtain:

\dfrac{6}{5}P'+P'=226\\\\\dfrac{6P'+5\times P'}{5}=226\\\\\dfrac{6P'+5P'}{5}=226\\\\11P'=226\times 5\\\\11P'=1130\\\\P'=\dfrac{1130}{11}=102.7272

Hence,

P=226-102.7272=123.2727

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

6 0
3 years ago
What is the result of gaining 10 pound then losing 20
kiruha [24]

Answer:

-10 pounds or 10 pounds loss

Step-by-step explanation:

you subreact 10-20 and you get -10

3 0
3 years ago
What’s the answer to this question
Makovka662 [10]
25......................
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3 years ago
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Plz plz plz help help❤️ With atleast some
RSB [31]

Answer:

the tables have a pattern of consistancy

Step-by-step explanation:

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3 years ago
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