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3 years ago

Explain how you think global winds can impact weather in an area.

Physics

1 answer:

weeeeeb [17]3 years ago

5 0

Answer:

As the wind travels across the earth, air masses and global winds do not travel in straight lines. in the Northern hemisphere air veers to the right and in southern hemisphere to the left. this motion can result in large circulating weather systems, as air blows away from or into a high or low pressure areas.

on earth the main differences in air pressure are caused by differences in temperatures. cool air produces high air pressure and warm air produces low air pressure.

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If an object is 16.76 cm in front of a convex mirror that has a focal length of 67.1 cm, how far behind the mirror will the imag

aniked [119]

F = focal lenght = 67.1 cm

u= distance between mirror and object = 16.76 cm

1/f = 1/v + 1/u

1/67.1 = -1/16.76 + 1/u

1/67.1 + 1/16.76 = 1/u

u = 13.41

7 0

1 year ago

A 0.015 kg marble moving to the right at 0.225 m/s makes an elastic head-on collision with a 0.030 kg shooter marble moving to t

bonufazy [111]

Answer:

0.09 m/s to the right

Explanation:

The principle of conservation of linear momentum states that in a system of colliding objects, the total momentum before collision is equal to the total momentum after collision, provided there is no external force.

The total momentum, in this question, is the sum of the momentum of the the two marbles. We assume velocity to the right is positive while to the left is negative. Thus, total initial momentum is

$P_i = 0.015\times0.225+ 0.030 \times(-0.180) = 0.002025$

After collision, the first marble goes left. Let the velocity of the other marble be v. Then we have

$P_f = 0.015\times(-0.315) + 0.030v = 0.030v - 0.004725$

Equating both momenta,

$P_i = P_f$

$0.002025 = 0.030v - 0.004725$

$v = 0.09 \text{ m/s}$

Hence, the larger goes right with a velocity of 0.09 m/s (since it has a positive sign).

4 0

3 years ago

Find the equivalent resistance of this parallel circuit with two strands.

svlad2 [7]

In a parallel circuit, the total resistance calculated from the individual resistances is computed from the formula: 1/Rt = 1/R1 + 1/R2. substituting R1 and R2, then
1/Rt = 1/7 + 1/49
1/Rt = 1/6.125 = 1/ 49/8
Rt = 49/8 <span>Ω

The total resistance hence is </span>49/8 Ω

6 0

3 years ago

Suppose you push horizontally with precisely enough force to make the block start to move, and you continue to apply the same am

Tcecarenko [31]

Answer:

Incomplete question,

This is the complete question

Suppose you push horizontally with precisely enough force to make the block start to move, and you continue to apply the same amount of force even after it starts moving. Find the acceleration ~a of the block after it begins to move. Express your answer in terms of some or all of the variables µs, µk, and m, as well as the acceleration due to gravity g.

Explanation:

Let the force that make the object to start moving be F,

Frictional force is opposing the motion, the body has to overcome two frictional forces acting in the opposite direction of the motion.

Also, weight and normal reaction are acting in vertical direction, the weight is acting downward while the reaction is acting upward.

Weight of the object is given as

W=mg

Analyzing the vertical motion i.e y-axis.

ΣF = ma

since the body is not moving upward, the a=0

N-W=0

Then, N=W

So, N=mg

So, from friction law

Fr=µN

For static

Fs=µsN

For kinetic or dynamic

Fk= µkN

Using newton law

Along x-axis

Before the body start moving we can get the Force and since the force is the same use to start the block in motion.

Then,

ΣF = ma

Since at static the body is not moving then, a=0

F-Fs=0

F=Fs

Since, Fs=µsN

F=Fs=µsN

Then, the force to keep the body in motion too is F=µsN

Now analyses when the body is in motion

ΣF = ma

F-Fk=ma

ma=F - Fk

Substituting F=µsN and Fk=µkN

ma=µsN - µkN

ma=N(µs - µk)

Since N=mg

Then, ma=mg(µs - µk)

m cancels out, then

a=g(µs - µk)

Then the acceleration of the body is given as "a=g(µs - µk)"

5 0

3 years ago

Which would fall with greater acceleration in a vacuum a leaf or a stone?

Sergeu [11.5K]

Because its a vacuum, there's no air resistance, they will fall at same time
Applying gravity acceleration rule g=9.8m/s which is taken as 10m/s sometimes.

3 0

3 years ago

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