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Crazy boy [7]
3 years ago
13

Please help me do that.​

Physics
1 answer:
Anika [276]3 years ago
3 0

Answer:

a) 22.2 N

Explanation:

To find load effort. Identify load, efficiency and velocity ratio (VR)

Here given:

  • Load = 100 N
  • Efficiency = 75%
  • VR (number of pulleys) = 6

Effort :

\rightarrow \sf \dfrac{MA}{VR} = \dfrac{Load \  \div \ efficiency }{VR} = \dfrac{100 \div 75 \% }{6} = 22.22 \ N

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The cylindrical tub of a dryer in a laundromat rotates counterclockwise about a horizontal axis at 41.5 rev/min as it dries the
frozen [14]

Answer:

\theta = 49.81^0

Explanation:

Given that:

\omega = 41.5 \ rev/min\\\\\omega = 41.5 *\frac{1}{60}* 2 \pi\\\\\omega = 4.45 \ rad/s\\\\\\diameter = 0.748 m

If we let the piece of the close lose contact at ∠θ;

Then ; from force balance;

we have:

\\\\mg sin \theta = \frac{mv^2}{r}\\\\sin \theta = \frac{2v^2}{dg}\\\\\theta = sin^{-1} (\frac{2v^2}{dg})

where;

v = \frac{\omega d}{2}\\\\v =  \frac{4.45 *0.748}{2}\\\\v = 1.6643\\\\v^2 = 2.77

Again:

\theta = sin^{-1}(\frac{2v^2}{dg})\\\\\theta = sin^{-1}( \frac{2*2.77}{0.74*9.8})\\\\\theta = 49.81^0

6 0
3 years ago
1) An object is hung using a metal spring. If now a current is passed through the spring, what will happen to this system?
son4ous [18]

Answer:

D) The spring will contract, raising the weight.

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According to the statement there is current that will enter the current through the metal ions that it has in its stratum. The passage of the current will generate within the spring a magnetic field that travels in a loop. That is, while the upper part of the spring which is also that of the spring acts as a north pole, the lower part of the spring and the magnetic field will act as the south pole. The position of the poles will generate an opposition effect that will generate an attraction to each other which will generate a contraction in the spring and an increase in weight on it.

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4 years ago
• (-/1 Points) DETAILS OSCOLPHYS2016 9.5.WA.040.
Tanya [424]

The force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.

<h3>Force exerted outside the wheel</h3>

The force exerted on the outside of the wheel can be determined by applying the principle of conservation of angular momentum as shown below.

∑τ = 0

  • Let the distance traveled by the load = 1.5 m
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∑τ = R(mg) - r(F)

rF = R(mg)

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Thus, the force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.

Learn more about angular momentum here: brainly.com/question/7538238

6 0
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