Question

You are standing on a ladder, helping with some repairs at home. You drop a hammer and it hits the floor at a speed of 4 feet per second. If the acceleration due to gravity (g) is 32 feet/second^2 , how far above the ground (h) was the hammer when you dropped it? Use the formula
V= square root 2gh


A. 16.0 feet
B. 1.0 foot
C. 0.25 feet
D. 0.5 feet

Answer 1

$h=\dfrac{v^2}{2g}=\dfrac{4^2}{2\cdot 32}=\dfrac{16}{64}=\dfrac{1}{4}=0.25$
Answer: C 0.25 feet.

Answer 2

Answer:

C 0.25Ft

Step-by-step explanation: