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Viktor [21]
3 years ago
14

What is the common angle of triangle PQT and triangle RSQ? Can someone explain this for me ?

Mathematics
1 answer:
adelina 88 [10]3 years ago
5 0
The angle on the lines sq and tq
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Write the symbols and use to find the next terms . 3,6,9,12​
Elodia [21]

Answer:

15

Step-by-step explanation:

the pattern is adding by three so 12+3=15

8 0
3 years ago
the relationship between money earned and hours worked is linear. joe computes the slope between (4, 30) and (12, 90), then comp
julia-pushkina [17]
Slope = rise/run =[y2-y1]/[x2-x1]

1) slope = [90 - 30] / [12 - 4] = 60 / 8 = 15/2

2) slope = [75 - 30] / [10 - 4] = 45 / 6 = 15 / 2

The slopps are equal.
6 0
3 years ago
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What is the common ratio for this geometric sequence 3,12,48,192,... A 16 B. 3 C. 4 D. 9
hram777 [196]

Answer:

4

Step-by-step explanation:

The common ratio is  found by taking the second term and dividing by the first term

12/3 = 4

We can check by taking the third term and dividing by the second

48/12 = 4

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3 0
3 years ago
Given the graph of the pre-image and image, identify the correct<br> coordinate transformation.
ziro4ka [17]

The preimage was shifted to the image by a translation 2 units right and 2 units up, so the answer is (x,y) \longrightarrow (x+2, y+2)

8 0
2 years ago
Help me please. <br>Help me please. <br>Help me please.
Gnesinka [82]
A)
To be similar triangles have to have equal angles
triangle ZDB' 
1)angle Z=90 degrees
triangle B'CQ
1) angle C 90 degrees

angle A'B'Q=90
DB'Z+A'B'Q+CB'Q=180, straight angle
DB'Z+90+CB'Q=180
DB'Z+CB'Q=90

triangle ZDB'
DZB'+DB'Z=180-90=90

DB'Z+CB'Q=90
DZB'+DB'Z=90
DB'Z+CB'Q=DZB'+DB'Z
2)CB'Q=DZB' (these angles from two triangles ZDB' and B'CQ )
3)so,angles DB'Z and B'QC are going to be equal because of sum of three angles in triangles =180 degrees and 2 angles already equal.
so this triangles are similar by tree angles
b)
B'C:B'D=3:4
B'D:DZ=3:2
CQ-?
DC=AB=21
DC=B'C+B'D (3+4= 7 parts)
21/7=3
B'C=3*3=9
B'D=3*4=12
B'D:DZ=3:2
12:DZ=3:2
DZ=12*2/3=8
B'D:DZ=CQ:B'C
3:2=CQ:9
CQ=3*9/2=27/2

c)
BC=BQ+QC=B'Q+QC
BQ' can be found by pythagorean theorem



3 0
3 years ago
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