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2 years ago

15

What two numbers multiply to get 40 and add to get 11

1 answer:

Trava [24]2 years ago

6 0

I got the factors of 40 but both numbers do not add up to 11. Negative numbers are not considered because the product and sum are positive numbers.

1 x 40 = 40 1 + 40 = 41
2 x 20 = 40 2 + 20 = 22
4 x 10 = 40 4 + 10 = 14
5 x 8 = 40 5 + 8 = 13

I also got the addends of 11 and solved each set to get the product
1 + 10 = 11 1 x 10 = 10
2 + 9 = 11 2 x 9 = 18
3 + 8 = 11 3 x 8 = 24
4 + 7 = 11 4 x 7 = 28
5 + 6 = 11 5 x 6 = 30

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Carlos walked to school on 14 of the 20 school days in February. Which value is equivalent to the fraction of the school days in

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Answer: A

Step-by-step explanation: 14/20 = 70%

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3 years ago

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A football team charges $30 per ticket and averages 20,000 people per game. Each person spend an average of $8 on concessions.Fo

olya-2409 [2.1K]

The ticket price that would maximize the total revenue would be $ 23.

Given that a football team charges $ 30 per ticket and averages 20,000 people per game, and each person spend an average of $ 8 on concessions, and for every drop of $ 1 in price, the attendance rises by 800 people, to determine what ticket price should the team charge to maximize total revenue, the following calculation must be performed:

20,000 x 30 + 20,000 x 8 = 760,000
24,000 x 25 + 24,000 x 8 = 792,000
28,000 x 20 + 28,000 x 8 = 784,000
26,000 x 22.5 + 26,000 x 8 = 793,000
27,200 x 21 + 27,200 x 8 = 788,000
26,400 x 22 + 26,400 x 8 = 792,000
25,600 x 23 + 25,600 x 8 = 793,600
24,800 x 24 + 24,600 x 8 = 792,000

Therefore, the ticket price that would maximize the total revenue would be $ 23.

Learn more in brainly.com/question/7271015

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2 years ago

35 solve the following syste

blondinia [14]

Part A: The solution is $(-0.923,5.692)$

Part B: The point $(3,7)$ is not in the solution set.

Explanation:

Part A: The given inequalities are $3 x+4 y>20$ and $x$

The solution can be determined by solving the two inequalities by substitution method.

Changing inequalities to equality, we have,

$x=3 y-18$ and $3 x+4 y=20$

Let us substitute $x=3 y-18$ in the equation $3 x+4 y=20$ , we get,

$3 (3y-18)+4 y=20$

$9y-54+4y=20$

$13y=74$

$y=5.692$

Substituting $y=5.692$ in $x=3 y-18$ , we get,

$x=3 (5.692)-18$

$=17.076-18$

$x=-0.923$

Thus, the solution set is $(-0.923,5.692)$

Part B: Now, we shall determine whether the point $(3,7)$ is in the solution set.

Let us substitute the point $(3,7)$ in the inequalities $3 x+4 y>20$ and $x$ , we get,

$3 (3)+4 (7)>20$

$9+28>20$

$37>20$

Also, substituting $(3,7)$ in $x$ , we get,

$3$

$3$

$3$

Since, the point $(3,7)$ does not satisfy one of the inequality $x$ , the solution set does not contain the point $(3,7)$

Thus, the point $(3,7)$ is not in the solution set.

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2 years ago

Use the Distributive Property to write each expression as an equivalent algebraic expression.

xxMikexx [17]

Answer:

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3 (7+a)

distribute 3 into parentheses:

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3 years ago

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Which equation is equivalent to the given equation? 7m + 11 = -4 (2m +3)

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Answer:

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Step-by-step explanation:

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3 years ago