widest to narrowest: y=3/2x2, y= -1/2x2, y= 1/4x2
Answer:
32√5
Step-by-step explanation:
We have the right triangles PQA and PQB as well as the given right triangle QAB.
cot(PAQ) = 2/5 = QA/PQ
cot(PBQ) = 3/5 = QB/PQ
cot(PAQ) / cot(PBQ) = (2/5) / (3/5) = 2/3
cot(PAQ) / cot(PBQ) = (QA/PQ) / (QB/PQ) = QA / QB
QA / QB = 2/3
QA = (2/3) QB
QB = (3/2) QA
By the Pythagorean Theorem we have:
(QA)² + 32² = (QB)²
(QA)² + 32² = (3/2 QA)²
(QA)² + 1024 = (9/4) (QA)²
(5/4) (QA)² = 1024
(QA)² = (4/5)1024 = 4096/5
QA = 64/√5
Solve for PQ.
cot(PAQ) = QA/PQ
PQ = QA / cot(PAQ)
PQ = (64/√5) / (2/5) = 32√5
The height of the tower is 32√5.
The range of the function in the graph given can be expressed as: D. 20 ≤ s ≤ 100.
<h3>What is the Range and Domain of a Function?</h3>
All the possible set of x-values that are plotted on the horizontal axis (x-axis) are the domain of a function. In order words, they are the inputs of the function.
On the other hand, all the corresponding set of x-values that are plotted on the vertical axis (y-axis) are the range of a function. In order words, they are the outputs of the function.
In the graph given below that shows a function, s is plotted on the vertical axis (y-axis), and its values starts from 20, up to 100. The range can be said to be all values of s that are from 20 to 100.
Therefore, the range of the function in the graph given can be expressed as: D. 20 ≤ s ≤ 100.
Learn more about functions on:
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➷ 40 = 1.8c + 32
Subtract 32 from both sides:
8 = 1.8c
Divide both sides by 1.8:
c = 4.4
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