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3 years ago

Did I do number 4 correctly?

Mathematics

2 answers:

Masja [62]3 years ago

5 0

The photo is not clear. nobody can see it.

Elenna [48]3 years ago

5 0

No, you did it incorrectly. The answer is y=-3
How I did this was;
2y+x=-15 x=3y
2y+3y=-15
If you multiply a whole number by a negative number you get a negative number, so I found a, number that could be multiplied into two different numbers that cloud be added together to have a sum of -15.
I really hope that made sense.

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Write each ratio statement as a fraction and reduce the two lowest terms 14:42

LuckyWell [14K]

<span>14:42 = 14/42 = 1/3
</span>This ones right sorry answered wrong question lol

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Diano4ka-milaya [45]

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1 year ago

What is the value of the fourth power of 10

Shalnov [3]

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3 years ago

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Find the equation of an exponential function in the form y = ab^x, given the points (0, 3) and (2, 108/25). Please simplify your

lilavasa [31]

We have the equation:

$y=a\cdot b^x$

We know two points and we will use them to calculate the parameters a and b.

The point (0,3) will let us know a, as b^0=1.

$\begin{gathered} y=a\cdot b^x \\ 3=a\cdot b^0=a \\ a=3 \end{gathered}$

Now, we use the point (2, 108/25) to calcualte b:

$\begin{gathered} y=3\cdot b^x \\ \frac{108}{25}=3\cdot b^2 \\ 3\cdot b^2=\frac{108}{25} \\ b^2=\frac{108}{25\cdot3}=\frac{108}{3}\cdot\frac{1}{25}=\frac{36}{25} \\ b=\sqrt[]{\frac{36}{25}} \\ b=\frac{\sqrt[]{36}}{\sqrt[]{25}} \\ b=\frac{6}{5} \end{gathered}$

Then, we can write the equation as:

$y=3\cdot(\frac{6}{5})^x$

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7 months ago

On Chris's birthday in 1992, he was half the age of his brother Joseph. On Chris' birthday in 1998, he was two-thirds the age of

aev [14]

Suppose in 1992 Chris was x years old, his brother was then 2x years old.
6 years later in 1998, Chris is (x+6) years old, his brother is (2x+6),
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x+6=(4/3)x+4
(4/3)x-x=6-4
(1/3)x=3
x=6
in 1992, Chris was 6, so in 2018 he will be 6+(2018-1992)=32 years old.

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3 years ago