Diagonal of the parallelogram divides the parallelogram in to two equal areas.
So area of parallelogram = 2(area of triangle)
According to the given diagram,
AB= 8, AD = 5 and BD = 11
So according to the Heron's formula,
Area of triangle =
and a, b and c are the three sides of the triangle
Area of triangle ABD =
So, area of parallelogram ABCD = 2(area of triangle ABD)
area of parallelogram ABCD = 2 (18.33)
area of parallelogram ABCD = 36.66
area of parallelogram ABCD = 36.7 sq. units
Answer:
135 degrees
Step-by-step explanation
Consider the attached diagram
we are required to find the bearing of the aeroplane,
Consider the right angled triangle BOE
|OB|=4 unit
|AB|=4 Units
The Bearing of the Aeroplane is therefore given:
(i)From North Clockwise as: 90+45 =135 degrees
(ii)From a North South Line as
Answer:
x ≈ 3.5 cm
Step-by-step explanation:
Using the sine ratio in the right triangle
sin23° = =
=
( multiply both sides by 9 )
9 × sin23° = x , then
x ≈ 3.5 cm ( to 1 dec. place )