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Marysya12 [62]
3 years ago
13

Let f(x) = x to the second power − 8x + 5. Find f(−1).

Mathematics
1 answer:
Alex17521 [72]3 years ago
4 0

Hello!

To find the value of f(-1), you need to substitute -1 into each x variable and solve. Remember to use PEMDAS when simplifying.

f(x) = x² - 8x + 5 (substitute -1 for x)

f(-1) = (-1)² - 8(-1) + 5 (simplify the exponent)

f(-1) = 1 - 8(-1) + 5 (multiply)

f(-1) = 1 + 8 + 5 (add alike terms)

f(-1) = 14

Therefore, the value of f(-1) is 14.

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Do your school bro: The Vikings were also known as Norsemen because<span>they sailed on ships called Norses.they came from the northland of Scandinavia.<span>they were barbarians.</span></span>
7 0
3 years ago
What is an equation of the line that passes through the points (-2,-5) and (-1,1)
alekssr [168]

Answer:

Slope = 6

Step-by-step explanation:

Slope = \frac{y^{2}-y^{1}  }{x^{2}-x^{1}  } =\frac{1-(-5)}{-1-(-2)}=\frac{1+5}{-1+2}=\frac{6}{1}=6

6 0
3 years ago
The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab
kolezko [41]

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable <em>X</em> thus follows a Poisson distribution with parameter, <em>λ</em> = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.  

The mean of the approximated distribution of X is:

μ = λ  = 250

The standard deviation of the approximated distribution of X is:

σ = √λ  = √250 = 15.8114

Thus, X\sim N(250, 250)

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

P(235

                             =P(-0.95

Thus, the value of P (235 < <em>X</em> < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.28

Thus, the value of P(48.

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.40

Thus, the value of P(48.

(d)

Let the sample size be <em>n</em>.

P(48

                             0.95=P(-z

The value of <em>z</em> for this probability is,

<em>z</em> = 1.96

Compute the value of <em>n</em> as follows:

z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241

Thus, the sample selected must be of size 240.

5 0
3 years ago
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BartSMP [9]

Answer: for the first it is not direct varition while for the second one it i s

Step-by-step explanation:

6 0
1 year ago
Find the sum<br>7/8+3/4 ​
ICE Princess25 [194]

Answer as an improper fraction =  13/8

This is equivalent to the mixed number   1 & 5/8

In decimal form, 13/8 = 1.625

=========================================

Work Shown:

3/4 = (3/4)*(2/2)

3/4 = (3*2)/(4*2)

3/4 = 6/8

----------

7/8 + 3/4

7/8 + 6/8

(7+6)/8

13/8

So 7/8 + 3/4 = 13/8

4 0
3 years ago
Read 2 more answers
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