Answer:
(0,3)
y=3
x=0
Step-by-step explanation:
x+5y=15
-3x+2y=6
solve the equation
x=15-5y
-3x+2y=6
substitute the value of x into an equation
-3(15-5y)+2y=6
distribute
-45-15y+2y=6
add 15 to 2
-45-17y=6
add 45 from both sides
17y=51
divide both sides by 17
y=3
substitute the value of y into an equation
x=15-5•3
multiply 5 to 3
x=15-15
subtract
x=0
(0,3)
Answer:
Step-by-step explanation:
The given equation is expressed as
x1 + 2x2 = -24- - - - - - - - --1
x1 + 7x2 = -11- - - - - - - --2
We would eliminate x1 by subtracting equation 2 from equation 1. It becomes
- 5x2 = - 13
Dividing both sides of the equation by - 5, it becomes
- 5x2/- 5 = - 13/- 5
x2 = 13/5
Substituting x2 = 13/5 into equation 2, it becomes
x1 + 7 × 13/5 = -11
x1 + 91/5 = - 11
x1 = - 11 - 91/5
x1 = - 146/5
Answer:
The common difference is -5/4
T(n) = T(0) - 5n/4,
where T(0) can be any number. d = -5/4
Assuming T(0) = 0, then first term
T(1) = 0 -5/4 = -5/4
Step-by-step explanation:
T(n) = T(0) + n*d
Let
S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240
S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220
S2 - S1
= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)
= (5+6+7+8 - 1 -2-3-4)d
= 4(4)d
= 16d
Since S2=220, S1 = 240
220-240 = 16d
d = -20/16 = -5/4
Since T(0) has not been defined, it could be any number.
Answer:
Day 2
Step-by-step explanation:
Every 20 days, one jar is full.
To find when it was 1/8 full, we multiply the 20 days by 1/8.
20 x 1/8 = 2
Day 2