Hi can someone please help me I need help please help me thank you
2 answers:
Answer:
the lines are perpendicular
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
x - 2y + 8 = 0 ( subtract x + 8 from both sides )
- 2y = - x - 8 ( divide all terms by - 2 )
y = x + 4 ← in slope- intercept form
with slope m =
Given also
2x + y + 1 = 0 ( subtract 2x + 1 from both sides )
y = - 2x - 1 ← in slope- intercept form
with slope m = - 2
Parallel lines have equal slopes
The slopes are not equal thus the lines are not parallel.
For lines to be perpendicular the product of their slopes = - 1
× - 2 = -1
Thus the 2 lines are perpendicular.
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The given quadratic polynomial is :
To find:
The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.
Solution:
We have,
Equate the polynomial with 0 to find the zeroes.
Splitting the middle term, we get
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Therefore, the required polynomial is .