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3 years ago

5

What is the value of a + bc when a=7, b = 4 and c = 1/2

1 answer:

saveliy_v [14]3 years ago

5 0

The value is 7 + 4(1/2), which equals 9.

7 + 4(0.5) = 7 + 2 = 9

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Which shows one way to determine the factors of x - 9x2 + 5x – 45 by grouping?

EleoNora [17]

Answer:

The last one.

Step-by-step explanation:

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3 years ago

BAKED GOODS Mary sells giant chocolate chip and peanut butter cookies for

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Answer:

(1.25c) + (1p) ≥ 25

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3 years ago

Which set of numbers could be the length of the sides

Svetllana [295]

Answer: Choice C) {6, 9, 12}

=======================================================

Explanation:

Something like choice A can't form a triangle because the first two sides add to 6+9 = 15, which is <u>not</u> longer than the third side 15. We need to have x+y > z to be true. The same goes for choice B as well because 3+3 = 6 is too small compared to the third side 7. Choice D is similar to choice A.

In short, we can rule out choices A, B, and D.

The only thing left is choice C. Picking any two sides leads to having that sum be larger than the third side

6+9 = 15 which is larger than 12
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6+15 = 21 which is larger than 9

So the conditions of the triangle inequality theorem work out here, and we have a triangle.

3 0

3 years ago

What is the equation of the line perpendicular to the line with zero slope passing through point (5,7)?

Mademuasel [1]

Answer:

perp. is -0 which is 0

y - 7 = 0(x - 5)

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6 0

3 years ago

A trader bought x mangoes at the rate of 4 mangoes for 10 naira five of the mangoes were bad so he sold the remaining at the rat

Ilya [14]

Answer:

20 mangoes.

Step-by-step explanation:

Given:

Total number of mangoes, a trader bought = $x$

A trader bought at the rate of 4 mangoes for 10 naira.

Five of the mangoes were bad.

He sold the remaining at the rate of 5 mangoes for 20 naira.

He made a gain of 10 naira

Question asked:

Total number of mangoes, a trader bought = $x$ = ?

Solution:

Unitary method

Cost price of 4 mangoes = 10 naira.

Cost price of 1 mango = $\frac{10}{4}$

Cost price of $x$ mango = $\frac{10}{4}\times x= \frac{5}{2} x$

As 5 of the mangoes were bad and he sold the remaining mangoes, then Total number of mangoes sold = $x-5$

Sale price of 5 mangoes = 20 naira

Sale price of 1 mango = $\frac{20}{5}$

Sale price $x-5$ of mango = $\frac{20}{5}\times(x-5)=4(x-5)=4x-20$

Now, as we know,

$Gain = Sale price - cost price$

$10 = 4x-20 -\frac{5}{2} x\\ 10=4x-\frac{5}{2} x-20\\10=\frac{8x-5x}{2} -20$

$10 =\frac{3x}{2} -20$

Adding both sides by 20

$30=\frac{3x}{2}$

Multiplying both sides by 2

$60 = 3x$

Dividing both sides by 3

$x=20$

Therefore, total number of mangoes, a trader bought is 20.

3 0

3 years ago