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Sever21 [200]
3 years ago
10

Tim earned $300 in five days. After the first day, he earned $10 more each day than the day before. How much did Tim earn on the

first day?
Mathematics
2 answers:
Vika [28.1K]3 years ago
8 0
Use the equation 300⇒5x to find how much tim made each day on average. 
x⇒60   so, Day 1: $60, Day 2: $70 etc.. so the equation 300=5x+10 suffices the problem. 300⇒5x+10 ⇒    290=5x
x=58
So, Tim earned $58 his first day. Hope this helped.
S_A_V [24]3 years ago
6 0
The given problem is based on arithmetic sequence
Sn = 300 (the sum of money in five days)
d = 10 (the difference day by day)
n = 5
The question asks how much Tim earn on the first day, we write it as a₁

The general formula to find the sum of a sequence is
n/2 (2a₁ + d(n-1)) = Sn

Input the numbers to the formula to find the value of a₁
n/2 (2a₁ + d(n-1)) = Sn
5/2 (2a₁ + 10(5-1)) = 300
5/2 (2a₁ + 10(4)) = 300
5/2 (2a₁ + 40) = 300
2a₁ + 40 = 300 × 2/5
2a₁ + 40 = 120
2a₁ = 120 - 40
2a₁ = 80
  a₁ = 80/2
  a₁ = 40

The first day, Tim earned $40
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Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court
Ksju [112]

Answer:

(a)\dfrac{92}{117}

(b)\dfrac{8}{39}

(c)\dfrac{25}{117}

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed)=P(MW)+P(WM)

=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

  • A man is appointed first and a woman is appointed next.
  • A woman is appointed first and a man is appointed next.
  • Two women are appointed

P(at least one woman is appointed)=P(MW)+P(WM)+P(WW)

P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}

In Part B, P(MW)+P(WM)=\frac{8}{39}

Therefore:

P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}

5 0
3 years ago
The straight line 3y = 5x + h - 6 intersect the x-axis at 4k, where h and k are constants. explain h in terms of k
inn [45]

When a function intersects with the x-axis, it's y value must be 0. That means when the straight line intersects with the axis, it's at the point (4k,0), so plugging those numbers into our original equation yields:

0=20k+h-6 \implies\\ 6=20k+h \implies \\ 6-20k=h

3 0
3 years ago
What is the sum of the finite arithmetic series (-5)+0+5+10+ ......+65
Alex17521 [72]

If you want to solve this problem using formulas, there are two important formulas:

t1  =  first term  =  -5          

tn  =  nth term  =  last term  =  -5

n  =  numbr of terms

Sn  =  sum of the n terms

tn  =  t1 + (n - 1)d     --->     65  =  -5 + (n - 1)(5)

                                          65  =  -5 + 5n - 5

                                          65  =  -10 + 5n

                                          75  =  5n

                                            n  =  15

Sn  =  n(t1 + tn)/2     --->     Sn  =  15(-5 + 65)/2

                                          Sn  =  450


So ur answer rounds up to 450


Letter c

:)

hope i helped 


~Luis

5 0
3 years ago
Write an expression please help me
qwelly [4]

I'm pretty sure it's

(24/3) + x.

Simplify it: 8 + x

4 0
3 years ago
Help help help help help pleases pelass thank you
Elodia [21]

Answer:

a' (-6,7) b' (-5,3) c'(-2,4)

Step-by-step explanation:

5 0
2 years ago
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