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2 years ago

In which step did karina make an error

1 answer:

3 0

Hi there!

Ok i would love to answer you but do you have answer choices, or the other part of the question or a image?

~Jada

You might be interested in

Find the roots of this equation 7xsquare - 5x - 2 = 0

Sophie [7]

Answer:

x = 1, -2/7

Step-by-step explanation:

You could use the quadratic equation but this can be factored into

(7x + 2) (x - 1). You can verify that by multiplying it out.

Since (7x + 2) (x - 1) = 0, if either factor is 0 then the equation would be equal to 0, thus we get x = 1, -2/7

7 0

2 years ago

Heights (in centimeters) and weights (in kilograms) of 7 supermodels are given below. Find the regression equation, letting the

Delvig [45]

The regression equation:
y = m x + b
m = ( 57 - 50 ) / ( 178 - 168 ) = 7 / 10 = 0.7
50 = 0.7 * 168 + b
50 = 117.6 + b
b = 50 - 117.6
b = - 67.6
y = 0.7 * x - 67.6
The graph is in the attachment.
The weight of supermodel who is 171 cm tall:
y = 0.7 * 171 - 67.6 = 119.7 - 67.6 = 52.1 kg

Download docx

6 0

3 years ago

Based on the markings which lines or segments must be parallel? Justify your answer

Lady bird [3.3K]

L and M are parallel, just like P and N because their angles with other segments are the same

3 0

3 years ago

Find the measurement of 0 in radians

Lina20 [59]

Answer:

5 pi/12

Step-by-step explanation:

To change degrees to radians, multiply by pi/180

75* pi/180

divide the top and bottom by 15

5 pi/12

6 0

2 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

3 years ago