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3 years ago

If jake can write 450 words in 15 minutes how much can he write in 20 minutes?

Mathematics

2 answers:

fomenos3 years ago

5 0

Answer:

450 divided by 15 is 30 so

he writes 30 words each minute

so add 150 to it. (because 30 x 5 = 150) i think the answer would be 600

Step-by-step explanation:

Yanka [14]3 years ago

4 0

Answer:

600 words

Step-by-step explanation:

To find how many words Jake can write in 20 minutes, you can find how many words he can write in 1 minute and multiply that by 20. Jake can write 30 words in a minute because 450 words divided by 15 minutes is 30. Then, multiply 30 by 20 which is 600.

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A facility has 150 beds and during a 30 day period they have 4,200 occupied bed days. What is their average percentage of occupa

natulia [17]

Answer:

Average percentage of occupancy = 93%.

Step-by-step explanation:

If a facility has 150 beds, then over a 30 day period they could have as many as 150 x 30 or 4,500 occupied beds. Since over the given 30 day period they only had 4,200 occupied beds, we can find the average percentage of occupancy by dividing the actual number by the expected number and multiplying by 100:

$\frac{actual}{expected} = \frac{4200}{4500}$ x 100 = 93%

3 0

3 years ago

Read 2 more answers

A ball is thrown in the air from a platform that is 96 feet above ground level with an initial vertical velocity of 32 feet per

pishuonlain [190]

Answer:

y = -16 (x - 1)^2 + 112

The object lands on the ground in approximately 3.6s

Explanation:

The equation given is that of a parabola.

Now the maximum (local) point of a parabola is the vertex. Therefore, if we want to rewrite our function in the form that would be used to find the maximum height, then that form must be the vertex form of a parabola.

The vertex form of a parabola is

$y=a(t-h)^2+k$

where (h, k) is the vertex.

The only question is, what is the vertex for our function h(t)?

Remember that if we have an equation of the form

$y=ax^2+bx+c$

then the x-coordinate of the vertex is

$h=-\frac{b}{2a}$

Now in our case b = 32 and a = -16; therefore,

$h=\frac{-32}{2(16)}=1$

We've found the value of the x-coordinate of the vertex. What about the y-coordinate? To get the y-coordinate, we put x = 1 into h(t) and get

$k=-16(1)+32(1)+96=112$

Hence, the y-coordindate is k = 112.

Therefore, the vertex of the parabola is (1, 112).

With the coordinates of the vertex in hand, we now write the equation of the parabola in vertex form.

$h(t)=a(t-1)^2+112$

The only problem is that we don't know what the value of a is. How do we find a?

Note that the point (0, 96) lies on the parabola. In other words,

$h(0)=-16(0)^2+32(0)+96=96$

Therefore, the vertex form of the parabola must also contain the point (0, 96).

Putting in t = 0, h = 96 into the vertex form gives

$96=a(0-1)^2+112$ $96=a+112$

subtracting 112 from both sides gives

$a=-16$

With the value of a in hand, we can finally write the equation of the parabola on vertex form.

$\boxed{h\mleft(t\mright)=-16\left(t-1\right)^2+112.}$

Now when does the object hit the ground? In other words, for what value of t is h(t) = 0? To find out we just have to solve the following for t.

$h(t)=0.$

We could either use h(t) = -16t^2 + 32t + 96 or the h(t) = -16(t - 1)^2 + 112 for the above equation. But it turns out, the vertex form is more convenient.

Thus we solve,